Answer
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Hint We will first find out the acceleration of the car. Finally we will find out the angle it makes with the vertical.
Formulae Used: $a = \frac{{(v - u)}}{t}$
Where, $a$ is the acceleration of the body, $v$ is the final velocity, $u$ is the initial velocity and $t$ is the time taken by the body.
Complete Step By Step Solution
Here,
\[u = {\text{ }}36{\text{ }}km{h^{ - 1}} = 10m{s^{ - 1}}\]
\[v = 0km{h^{ - 1}} = 0m{s^{ - 1}}\]
\[t = 5s\]
Now,
\[{a_{car}} = \frac{{(0 - 10)}}{5}\]
Now,
\[{a_{}} = - 2m{s^{ - 2}}\]
\[\begin{gathered}
tan\theta = \frac{a}{g} = \frac{2}{{10}} = \frac{1}{5} \\
\\
\end{gathered} \]
Thus, the answer turns out to be \[\theta = ta{n^{ - 1}}(\frac{1}{5})\] which is (C).
But,
Also,
If we take
\[\begin{gathered}
sin\theta = \frac{2}{{10}} = \frac{1}{5} \\
\\
\end{gathered} \]
\[ \Rightarrow \theta = si{n^{ - 1}}(\frac{1}{5})\]
Hence, (B) is also correct.
Note We got the value of \[sin\theta \] , we took \[{a_{net}} = \sqrt {{a^2} + {g^2}} \] an d value turns out to be \[10m{s^{ - 2}}\]. Also, we took only the magnitude as it only plays the role to form the angle.
Formulae Used: $a = \frac{{(v - u)}}{t}$
Where, $a$ is the acceleration of the body, $v$ is the final velocity, $u$ is the initial velocity and $t$ is the time taken by the body.
Complete Step By Step Solution
Here,
\[u = {\text{ }}36{\text{ }}km{h^{ - 1}} = 10m{s^{ - 1}}\]
\[v = 0km{h^{ - 1}} = 0m{s^{ - 1}}\]
\[t = 5s\]
Now,
\[{a_{car}} = \frac{{(0 - 10)}}{5}\]
Now,
\[{a_{}} = - 2m{s^{ - 2}}\]
\[\begin{gathered}
tan\theta = \frac{a}{g} = \frac{2}{{10}} = \frac{1}{5} \\
\\
\end{gathered} \]
Thus, the answer turns out to be \[\theta = ta{n^{ - 1}}(\frac{1}{5})\] which is (C).
But,
Also,
If we take
\[\begin{gathered}
sin\theta = \frac{2}{{10}} = \frac{1}{5} \\
\\
\end{gathered} \]
\[ \Rightarrow \theta = si{n^{ - 1}}(\frac{1}{5})\]
Hence, (B) is also correct.
Note We got the value of \[sin\theta \] , we took \[{a_{net}} = \sqrt {{a^2} + {g^2}} \] an d value turns out to be \[10m{s^{ - 2}}\]. Also, we took only the magnitude as it only plays the role to form the angle.
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