Question

1 weber is equivalent of
A. ${10^{ - 8}}$ Maxwell
B. ${10^{12}}$ Maxwell
C. ${10^8}$ Maxwell
D. ${10^4}$ Maxwell

Answer 1

Hint: Weber is the SI unit of magnetic flux, and Maxwell on the other hand is the unit of magnetic flux in the Gaussian and electromagnetic system of units, both of which are CGS units. In the derived form the units of magnetic flux are volt-second, so convert these into their relevant CGS units for the required answer.

Complete step by step answer:
The term flux implies some kind of flow. Flux is the property of any vector field. The magnetic flux is a property of the magnetic field. The surface integral of the normal component of the magnetic field flux density B passing through a surface is defined as the Magnetic flux through this surface. It is denoted by$\varphi {\text{ or }}{\phi _B}$.
Maxwell is the CGS i.e., the centimetre-gram-second unit of magnetic flux. It is denoted by the symbol ‘Mx’. Maxwell is defined as the total flux across a surface of one square centimeter which is perpendicular to a magnetic field of strength one gauss.
$1{\text{ Maxwell}} = 1{\text{ Gauss}} \times c{m^2}$
The SI unit of Magnetic Flux is Weber. It is given by the symbol ‘Wb’. The Weber in definition is,” the magnetic flux that, linking a circuit of one turn, will produce in it an electromotive force of one volt if it were reduced to zero at an uniform rate of one second”.
The relation between Weber and Maxwell is that-
1 Weber is equivalent to 100000000 or ${10^8}$ Maxwell.
1Wb= ${10^8}$ Maxwell
Additional Information:
1. The unit weber is named after Wilhelm Eduard Weber who was a German physicist.
2. Magnetic flux is measured using a flux meter.
3. The flux density of one $Wb/{m^2}$ is one Tesla.

Note: For the conversion of any and all physical quantities in one unit system to another, one needs to just multiply them to the factor values of their derived quantities in the respective system they are being converted to. Additionally, for conversion of a SI formula into CGS replace ${\varepsilon _ \circ }{\text{ to }}\dfrac{1}{{4\pi \times {{10}^{ - 3}}{c^2}}}$ and ${\mu _ \circ }{\text{ to }}4\pi \times {10^{ - 7}}$.