
If centre of a regular hexagon is at origin and one of the vertexes on argand diagram is $1 + 2{\rm{i}}$ then its perimeter is
A. $2\sqrt 5$
B. $6\sqrt 2$
C. $4\sqrt 5$
D. $6\sqrt 5$
Answer
226.8k+ views
Hint: InIn our case, we are provided the information that we have to assume that centre of a regular hexagon is at origin and one of the vertexes on argand diagram is 1 + 2{\rm{i}} and we are to determine the perimeter of the regular hexagon. For that, we have to we have to use the Pythagoras theorem to determine the radial distance between origin to vertex and also perimeter formula of regular hexagon to determine the desired answer.
Formula Used: The regular hexagon’s perimeter can be calculated using the formula
$P = S \times 6$
Here, S is equal to the measurement of one side.
Complete step by step solution: Considering that the origin is at the centre of a regular hexagon and one of the vertices on argand dig,
$\left( {1 + 2i} \right)$

We have been already known that,
Six equilateral triangles form a regular hexagon.
As a result, the distance between the centre and any vertex is equal to the length of an external side.
The centre is loaded at $\left( {0,0} \right)$ and the vertex is loaded at
$\left( {1,2} \right)$
The Pythagorean Theorem can be used to calculate the radial distance from the origin to the vertex:
$ \Rightarrow r = \sqrt {{1^2} + {2^{2}}}$
On solving the terms inside the root, we get
$ \Rightarrow r = \sqrt 5 $
As we know that,
Six equal sides make up a regular hexagon.
Therefore, here each side length in this figure is
$\sqrt 5$
As we aware that the formula for a regular hexagon's perimeter is
$P = S \times 6$ ---- (1)
Here, S is equal to the measurement of one side.
The measurement of one side is found as,
$\sqrt 5$
Now, we have to substitute the value on the formula
$P = S \times 6$
Therefore, we get
$= 6\sqrt 5$
Therefore, in a regular hexagon if one of the vertexes on argand diagram is 1 + 2{\rm{i}} then its perimeter is
$6\sqrt 5$ Units
Option ‘D’ is correct
Note: Student should be careful while soling this type of problem because; it includes some formulas to be remembered correctly. So, one should be very cautious in applying formulas as there are many types of hexagon, formulas might be confusable. And in order to get the desired solution we should apply the exact perimeter formula of regular hexagon.
Formula Used: The regular hexagon’s perimeter can be calculated using the formula
$P = S \times 6$
Here, S is equal to the measurement of one side.
Complete step by step solution: Considering that the origin is at the centre of a regular hexagon and one of the vertices on argand dig,
$\left( {1 + 2i} \right)$

We have been already known that,
Six equilateral triangles form a regular hexagon.
As a result, the distance between the centre and any vertex is equal to the length of an external side.
The centre is loaded at $\left( {0,0} \right)$ and the vertex is loaded at
$\left( {1,2} \right)$
The Pythagorean Theorem can be used to calculate the radial distance from the origin to the vertex:
$ \Rightarrow r = \sqrt {{1^2} + {2^{2}}}$
On solving the terms inside the root, we get
$ \Rightarrow r = \sqrt 5 $
As we know that,
Six equal sides make up a regular hexagon.
Therefore, here each side length in this figure is
$\sqrt 5$
As we aware that the formula for a regular hexagon's perimeter is
$P = S \times 6$ ---- (1)
Here, S is equal to the measurement of one side.
The measurement of one side is found as,
$\sqrt 5$
Now, we have to substitute the value on the formula
$P = S \times 6$
Therefore, we get
$= 6\sqrt 5$
Therefore, in a regular hexagon if one of the vertexes on argand diagram is 1 + 2{\rm{i}} then its perimeter is
$6\sqrt 5$ Units
Option ‘D’ is correct
Note: Student should be careful while soling this type of problem because; it includes some formulas to be remembered correctly. So, one should be very cautious in applying formulas as there are many types of hexagon, formulas might be confusable. And in order to get the desired solution we should apply the exact perimeter formula of regular hexagon.
Recently Updated Pages
If centre of a regular hexagon is at origin and one class 11 maths JEE_Advanced

If 16 identical pencils are distributed among 4 children class 11 maths JEE_Advanced

The students S1 S2 S10 are to be divided into 3 groups class 11 maths JEE_Advanced

If nCr 1 + n + 1Cr 1 + n + 2Cr 1 + + 2nCr 1 2n + 1Cr2 class 11 maths JEE_Advanced

Which of the following is true A ain ab B bcsubset class 11 maths JEE_Advanced

What is the value of the integral intlimits0pi esin class 11 maths JEE_Advanced

Trending doubts
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

JEE Advanced 2026 Revision Notes for Practical Organic Chemistry

IIT CSE Cutoff: Category‐Wise Opening and Closing Ranks

IIT Fees Structure 2025

Other Pages
JEE Main 2026: City Intimation Slip and Exam Dates Released, Application Form Closed, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

NCERT Solutions For Class 11 Maths Chapter 10 Conic Sections (2025-26)

