Question

Which set have the strongest tendency to form anions?
(A) \[Ga,In,Te\]
(B) $Ns,Mg,As$
(C) $N,O,F$
(D) $V,Cr,Mn$

Answer 1

Hint: As we know that Non-metals having very strong tendency to form the anions and we also know that metals have high power of formation of cation. We have to choose the correct answer from the above given option that which set is the strongest tendency to form the anions.

Complete Step by Step Solution:
From analyzing the above statement we get that we have to choose non metal which have the highest tendency to form the anions. We know that nitrogen, oxygen and fluorine are the most electronegative element as comparison to the option given above from this we can say that: They also accept electrons more easily from the another elements as compared to the others because of their electronegativity,

From that conclusion we get that when nitrogen, oxygen and fluorine are reacted with any element they can easily receive electrons from their presence of highest electron receiving capability. As a result, they can receive electrons and form negative ions which are called by the name of anions. Therefore, from getting full detail we get that $N,O,F$ (Nitrogen, Oxygen and Fluorine) is the correct answer.
Hence, the correct option is (C).

Note: In this question there are two major terms which are very useful for us which are electropositive element and electronegative element. Electropositive elements are those elements when they are reacted with any element that donated their electron present in their outermost shell and get positive ions that are called electropositive elements. Similarly, when an electronegative element reacts to any other element they receive electrons from the other element and form negative ions, that elements are known as electronegative elements.