
Which of the following statements is true as per the second law of thermodynamics for an isolated, ordered system?
A) Heat will flow into the system
B) Heat will flow out of the system
C) Work will be done by the system
D) Work will be done on the system
E) The entropy within the system will increase
Answer
233.1k+ views
Hint: All processes are caused by energy transfers where a part of the useful work is always dissipated to thermal heat which is accompanied with entropy generation. The changes in entropy for a universe can never be negative.
Complete step by step answer:
The second law of thermodynamics states that, “the total entropy of an isolated system can never drop over time, and remains constant only if all processes are reversible.”
Isolated systems always try to evolve spontaneously towards establishing thermodynamic equilibrium.
Let the entropy change of the universe be denoted by $\Delta {S_{univ}}$ and is equal to the sums of the changes in entropy of the system and surroundings:
$\Delta {S_{univ}} = \Delta {S_{sys}} + \Delta {S_{surr}}$
$ \Rightarrow \Delta {S_{univ}} = \dfrac{{{q_{sys}}}}{T} + \dfrac{{{q_{surr}}}}{T}$
For an isothermal reversible expansion, heat absorbed by the system from the surroundings is:
${q_{rev}} = nRT\ln \dfrac{{{V_2}}}{{{V_1}}}$
As the amount of heat absorbed by the system is equal to the heat lost by the surrounding, ${q_{sys}} = - {q_{surr}}$therefore, for a truly reversible process, the entropy change is equal to:
$\Delta {S_{univ}} = \dfrac{{nRT\ln \dfrac{{{V_2}}}{{{V_1}}}}}{T} + \dfrac{{ - nRT\ln \dfrac{{{V_2}}}{{{V_1}}}}}{T} = 0$
For an irreversible process, the entropy change is however positive:
$ \Rightarrow {q_{sys}} = nRT\ln \dfrac{{{V_2}}}{{{V_1}}} > 0$
$ \Rightarrow {q_{surr}} = nRT\ln \dfrac{{{V_4}}}{{{V_3}}} > 0$
$ \Rightarrow \Delta {S_{univ}} = \dfrac{{{q_{sys}}}}{T} + \dfrac{{{q_{surr}}}}{T} > 0$
$\therefore \Delta {S_{univ}} = \Delta {S_{sys}} + \Delta {S_{surr}} \geqslant 0$
Thus, the entropy within the system always increases in an isolated and ordered system as per second law of thermodynamics.
Option (E) is correct.
Note: The Second Law of Thermodynamics is a universal law and it is valid without any exceptions: in closed or open systems, in equilibrium or non-equilibrium, in inanimate or animate systems - that is, in all space and time scales. In reality, truly reversible processes never really occur; thus it is safe to tell that the entropy always increases for all irreversible processes.
Complete step by step answer:
The second law of thermodynamics states that, “the total entropy of an isolated system can never drop over time, and remains constant only if all processes are reversible.”
Isolated systems always try to evolve spontaneously towards establishing thermodynamic equilibrium.
Let the entropy change of the universe be denoted by $\Delta {S_{univ}}$ and is equal to the sums of the changes in entropy of the system and surroundings:
$\Delta {S_{univ}} = \Delta {S_{sys}} + \Delta {S_{surr}}$
$ \Rightarrow \Delta {S_{univ}} = \dfrac{{{q_{sys}}}}{T} + \dfrac{{{q_{surr}}}}{T}$
For an isothermal reversible expansion, heat absorbed by the system from the surroundings is:
${q_{rev}} = nRT\ln \dfrac{{{V_2}}}{{{V_1}}}$
As the amount of heat absorbed by the system is equal to the heat lost by the surrounding, ${q_{sys}} = - {q_{surr}}$therefore, for a truly reversible process, the entropy change is equal to:
$\Delta {S_{univ}} = \dfrac{{nRT\ln \dfrac{{{V_2}}}{{{V_1}}}}}{T} + \dfrac{{ - nRT\ln \dfrac{{{V_2}}}{{{V_1}}}}}{T} = 0$
For an irreversible process, the entropy change is however positive:
$ \Rightarrow {q_{sys}} = nRT\ln \dfrac{{{V_2}}}{{{V_1}}} > 0$
$ \Rightarrow {q_{surr}} = nRT\ln \dfrac{{{V_4}}}{{{V_3}}} > 0$
$ \Rightarrow \Delta {S_{univ}} = \dfrac{{{q_{sys}}}}{T} + \dfrac{{{q_{surr}}}}{T} > 0$
$\therefore \Delta {S_{univ}} = \Delta {S_{sys}} + \Delta {S_{surr}} \geqslant 0$
Thus, the entropy within the system always increases in an isolated and ordered system as per second law of thermodynamics.
Option (E) is correct.
Note: The Second Law of Thermodynamics is a universal law and it is valid without any exceptions: in closed or open systems, in equilibrium or non-equilibrium, in inanimate or animate systems - that is, in all space and time scales. In reality, truly reversible processes never really occur; thus it is safe to tell that the entropy always increases for all irreversible processes.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

