Answer
Verified
35.4k+ views
Hint: The elements beryllium, magnesium, calcium and barium belong to group 2 of the periodic table. These are called alkaline Earth metals. Electrode potential is defined as the tendency of a chemical species to gain or lose electrons.
Complete Step by Step Solution:
The general outer electronic configuration of alkaline earth metals is
\[{\rm{n}}{{\rm{s}}^{\rm{2}}}\].
These elements have two electrons in the S orbital of the valency cell. These elements lose two electrons to undergo oxidation.
\[{\rm{M}} \to {{\rm{M}}^{{\rm{2 + }}}}{\rm{ + 2}}{{\rm{e}}^{\rm{ - }}}\] where M = alkaline earth metal
These metals are strong reducing agents. Reducing agents are the chemical species that reduce other chemical species and undergo oxidation themselves. The oxidation potential is defined as the measure of the tendency of an element to lose electrons. Oxidation potential increases on moving from top to bottom in a group. This is because on moving down the group atomic size increases. Electrons are added to higher energy levels. Valence electrons are not closely held by the nucleus. The loss of electrons is easier as we move down the group.
Out of the given options, beryllium has the smallest atomic size. The loss of electrons or oxidation is difficult. Beryllium has the least oxidation potential.
We know that \[{\rm{oxidation potential = }}\left( {{\rm{ - reduction potential}}} \right)\].
As Be has the least oxidation potential, it has the highest reduction potential.
So, option A is correct.
Note: As the atomic size increases down the group, the electropositive character which is the tendency to lose electrons increases on moving from Be to Ba. The oxidation potential is defined as the measure of the tendency of an element to get oxidised i.e., to lose electrons. The reduction potential is defined as the measure of the tendency of an element to get reduced i.e., to lose electrons.
Complete Step by Step Solution:
The general outer electronic configuration of alkaline earth metals is
\[{\rm{n}}{{\rm{s}}^{\rm{2}}}\].
These elements have two electrons in the S orbital of the valency cell. These elements lose two electrons to undergo oxidation.
\[{\rm{M}} \to {{\rm{M}}^{{\rm{2 + }}}}{\rm{ + 2}}{{\rm{e}}^{\rm{ - }}}\] where M = alkaline earth metal
These metals are strong reducing agents. Reducing agents are the chemical species that reduce other chemical species and undergo oxidation themselves. The oxidation potential is defined as the measure of the tendency of an element to lose electrons. Oxidation potential increases on moving from top to bottom in a group. This is because on moving down the group atomic size increases. Electrons are added to higher energy levels. Valence electrons are not closely held by the nucleus. The loss of electrons is easier as we move down the group.
Out of the given options, beryllium has the smallest atomic size. The loss of electrons or oxidation is difficult. Beryllium has the least oxidation potential.
We know that \[{\rm{oxidation potential = }}\left( {{\rm{ - reduction potential}}} \right)\].
As Be has the least oxidation potential, it has the highest reduction potential.
So, option A is correct.
Note: As the atomic size increases down the group, the electropositive character which is the tendency to lose electrons increases on moving from Be to Ba. The oxidation potential is defined as the measure of the tendency of an element to get oxidised i.e., to lose electrons. The reduction potential is defined as the measure of the tendency of an element to get reduced i.e., to lose electrons.
Recently Updated Pages
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
The path difference between two waves for constructive class 11 physics JEE_MAIN
What is the difference between solvation and hydra class 11 chemistry JEE_Main
IfFxdfrac1x2intlimits4xleft 4t22Ft rightdt then F4-class-12-maths-JEE_Main
Three point particles of mass 1 kg 15 kg and 25 kg class 11 physics JEE_Main
Which of the following explanation is best for not class 12 chemistry JEE_Main
Other Pages
Two identical charged spheres suspended from a common class 12 physics JEE_Main
Oxidation state of S in H2S2O8 is A 6 B 7 C +8 D 0 class 12 chemistry JEE_Main
Explain the construction and working of a GeigerMuller class 12 physics JEE_Main
The mole fraction of the solute in a 1 molal aqueous class 11 chemistry JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main