Question

The relatively high boiling point of HF is due to
A Hydrogen bonding
B Covalent bonding
C Unshared electron pair on F
D Being a halogen acid

Answer 1

Hint: Group 17 elements are known as halogens. These elements just need one more electron to achieve a perfect noble gas configuration. Out of all the halogens F is the most electronegative element, in fact F is the most electronegative element in the periodic table. Due to the small size of F, F can attract shared pairs of electrons towards itself effectively.

Complete step-by-step answer:The group of hydrogen halides consists of particular diatomic inorganic compounds having the chemical formula HX, where X is one of the halogens from fluorine to astatine. We are aware that one of the fundamental characteristics of hydrogen halides is that they are gases that do dissolve in water to produce acids, also known as hydrohalic acids.
H-F bonds are significantly more polar than N-H bonds because fluorine is more electronegative than nitrogen. A hydrogen bond between HF molecules is substantially stronger than one between $\text{N}{{\text{H}}_{\text{3}}}$molecules because of the high partial charges on the H and F in HF. Thus, the strong H-bond is what gives HF its high boiling point. Each HF molecule forms 2-H bonds, one through the F atom and one through H atom.

Option ‘A’ is correct

Note: A hydrogen atom that is bound to a highly electronegative atom and another highly electronegative atom that is close by interact with one another to form hydrogen bonds, which are an unique kind of attractive intermolecular interactions. This process is known as hydrogen bonding.