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The reaction\[C{{H}_{3}}C{{H}_{2}}I+KO{{H}_{(aq)}}\xrightarrow{{}}C{{H}_{3}}C{{H}_{2}}OH+KI\], is classified as:
(A) Electrophilic substitution
(B) Nucleophilic substitution
(C) Elimination
(D) Addition

Answer
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Hint:There are two types of substitution reactions.
Electrophilic substitution reaction: In this reaction an electrophile is going to replace another electrophile in the chemical it is called as electrophilic substitution reaction
Nucleophilic substitution reaction : In this reaction a nucleophile is going to replace a

Complete step by step solution:
> The given reaction is as follows.
\[C{{H}_{3}}C{{H}_{2}}I+KO{{H}_{(aq)}}\xrightarrow{{}}C{{H}_{3}}C{{H}_{2}}OH+KI\]
In the above reaction the reactant is ethyl iodide.
- The product is ethyl alcohol.
- In ethyl iodide the nucleophile is iodide (\[{{I}^{-}}\]).
- In ethyl alcohol the nucleophile is hydroxide (\[O{{H}^{-}}\]).
- Means in the reaction iodide is replaced with hydroxide.
- Means one nucleophile is substituted by another nucleophile.
Therefore, the reaction is a Nucleophilic substitution reaction.
> Coming to given options, Option A, electrophilic substitution, it is wrong because in the given reaction electrophilic substitution is not taking place.
> Coming to option C, Elimination, it is also wrong because there is no double bond in the given product.
> Coming to option D, Addition, it is also wrong because there is a double bond in the given reactant.
> Coming to option B, Nucleophilic substitution. It is correct. In the given reaction Nucleophilic substitution is taking place.
So, the correct option is B.

Note: Don’t be confused with the terms electrophile and nucleophile.
Electrophile – it is positively charged and attracts negative charge towards it.
Nucleophile – it is negatively charged and attracts positive charge towards it.