
The displacement of a particle in simple harmonic motion in one time period is:
A. A
B. 2A
C. 4A
D. Zero
Answer
233.1k+ views
Hint:In this question we are given a particle which is in simple harmonic motion and we are asked to find the total displacement of the same particle from the given four options, we will use the formula for the initial position of the particle and then will find the position of the same particle after one time period and then will find the net displacement.
Formula used:
The formula for initial position of the particle in a simple harmonic motion is given as,
\[y = A\sin \left( {\omega t + \phi } \right)\]
Here in the equation,
\[\left( {\omega t + \phi } \right)\] is the phase of the motion, \[\phi \] is the initial phase of the motion of particles and \[A\] is the amplitude.
Complete step by step solution:
We can write this equation simple harmonic motion as
\[y = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\]
Since, \[\omega = \dfrac{{2\pi }}{T}\]..... (the time period of a particle is inversely proportional to frequency)
Now, let us consider the position of the same particle which is in simple harmonic motion after one time period, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}\left( {t + T} \right) + \phi } \right)\]
Further solving this equation, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}t + 2\pi + \phi } \right)\]
Now, the net displacement of the particle in simple harmonic motion in one time period will be,
\[d = {y_t} - y\\ \Rightarrow d = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\, - A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\,\\ \therefore d = 0\]
Hence we can say that the net displacement of the particle is zero.
Therefore, option D is correct.
Note:In one time period the particle in harmonic motion comes to the same point from where it started, in this case, the initial position of the particle becomes the same as the final position so the displacement of the particle remains zero. The displacement of a particle or wave is measured from the equilibrium position of the particle.
Formula used:
The formula for initial position of the particle in a simple harmonic motion is given as,
\[y = A\sin \left( {\omega t + \phi } \right)\]
Here in the equation,
\[\left( {\omega t + \phi } \right)\] is the phase of the motion, \[\phi \] is the initial phase of the motion of particles and \[A\] is the amplitude.
Complete step by step solution:
We can write this equation simple harmonic motion as
\[y = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\]
Since, \[\omega = \dfrac{{2\pi }}{T}\]..... (the time period of a particle is inversely proportional to frequency)
Now, let us consider the position of the same particle which is in simple harmonic motion after one time period, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}\left( {t + T} \right) + \phi } \right)\]
Further solving this equation, we have
\[{y_T} = A\sin \left( {\dfrac{{2\pi }}{T}t + 2\pi + \phi } \right)\]
Now, the net displacement of the particle in simple harmonic motion in one time period will be,
\[d = {y_t} - y\\ \Rightarrow d = A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\, - A\sin \left( {\dfrac{{2\pi }}{T}t + \phi } \right)\,\\ \therefore d = 0\]
Hence we can say that the net displacement of the particle is zero.
Therefore, option D is correct.
Note:In one time period the particle in harmonic motion comes to the same point from where it started, in this case, the initial position of the particle becomes the same as the final position so the displacement of the particle remains zero. The displacement of a particle or wave is measured from the equilibrium position of the particle.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

