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Magnetic field inside a toroidal solenoid is ?

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Last updated date: 16th Jun 2024
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Answer
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Hint: Due to a current carrying element, study the formation of magnetic fields. The concept of ampere’s circuital laws as an alternative to Biot Savart Law and the right hand thumb rule to be applied to find there magnetic field from the direction of the current flow. In the form of a helix about an axis, the current carrying wire around spirally is known as solenoid or coil.

Complete step-by-step solution:
The independent of the radius of the toroid is the magnetic field inside the toroidal solenoid. In the open space inside the magnetic field (point P) and to the toroid (point Q) is zero. According to Ampere's law, the net current is zero, then the magnetic field must be zero. Therefore, outside the solenoid’s radius for locations, the magnetic field is zero. Like a solenoid bent a toroid looks the same into a circular shape such as to close itself into a loop like structure.
The magnetic field in toroidal solenoid is not uniform, it is largest along the inner ring and smallest at the outer edge of the ring. For N numbers of loops in the coil the magnetic field will be
\[B = \dfrac{{{\mu _0}NI}}{{2\pi r}}\]
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Note: The magnetic field inside and outside the toroid is zero. It is a hollow circular ring. When the electric charge and current moves within the ring the magnet magnetic fields are created or produced. On a stationary change present in the magnetic force, no magnetic fields are produced.