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# Integrate $\int {{{\left( {\frac{{1 - z}}{z}} \right)}^2}dz}$.  Answer Verified
Hint- First, We simplify this equation by using of basic formula of algebra and integrate with respect to $z$
$\int {{{\left( {\frac{{1 - z}}{z}} \right)}^2}dz}$
$\int {\frac{{{{\left( {1 - z} \right)}^2}}}{{{z^2}}}dz}$
Here we use ${\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab$
$\int {\frac{{\left( {1 + {z^2} - 2z} \right)}}{{{z^2}}}dz}$
Whole equation is divided by ${z^2}$
$\int {\left( {\frac{1}{{{z^2}}} + 1 - \frac{2}{z}} \right)dz}$
Now, Integrate with respect to $z$
$- \frac{1}{z} + z - 2{\log _e}z +$$c$ (here $c$is an integral constant)
Ans.
Note- In this type of question first we simplify the equation after that apply basic formula of integral

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CBSE Class 12 Maths Formulas  Integration  CBSE Class 12 Maths Chapter-12 Linear Programming Formula  Differentiation and Integration  Continuous Integration  Integration Questions  Methods of Integration  Integration by Substitution  CBSE Class 12 Maths Chapter-7 Integrals Formula  CBSE Class 12 Maths Chapter-13 Probability Formula  