
If, in defining the specific heat, the temperature is represented in \[{}^\circ F\] instead of \[{}^\circ C\] then the numerical value of specific heat will
A) be converted to heat capacity
B) remain unchanged
C) decrease
D) increase
Answer
233.1k+ views
Hint: Specific heat refers to the ratio of the quantity of heat that we require to raise the temperature of a body by one degree that we need to increase the temperature of an equivalent mass of liquid (water) by one degree. Heat capacity represents the ability of a substance to absorb heat energy.
Complete step by step solution:
Let’s say \[Q\] amount of heat is needed to raise the temperature of a body of certain mass by \[1{}^\circ C\] and amount of heat is needed to raise the temperature of an equivalent mass of water by \[1{}^\circ C\]
From the definition of specific heat mentioned in the hint, specific heat can be given as \[\dfrac{Q}{q}\]
Now we all know that \[180\] divisions on the Fahrenheit scale correspond to \[100\] divisions of the Celsius scale.
Hence we can say that \[1{}^\circ F\] corresponds to \[{{\left( \dfrac{100}{180} \right)}^{{}^\circ }}C={{\left( \dfrac{5}{9} \right)}^{{}^\circ }}C\]
Hence the amount of heat needed to raise the temperature of the substance by one degree on the Fahrenheit will be \[\left( \dfrac{5}{9} \right)Q\]
Similarly, the amount of heat needed to raise the temperature of water by one degree on the Fahrenheit scale will be \[\left( \dfrac{5}{9} \right)q\]
Calculating the new specific heat corresponding to degree Fahrenheit, we get
specific heat \[=\dfrac{\left( \dfrac{5}{9} \right)Q}{\left( \dfrac{5}{9} \right)q}=\dfrac{Q}{q}\]
Hence we can clearly see that the specific heat remains unchanged even if the temperature is represented on the Fahrenheit scale instead of the Celsius scale.
Hence, Option (B) is the correct answer.
Note:Students often get confused with specific heat and specific heat capacity and end up doing blunders. Specific heat is a ratio whereas specific heat capacity is a measure of the amount of heat necessary to raise the temperature of one gram of a pure substance by one degree. Be mindful of the difference.
Complete step by step solution:
Let’s say \[Q\] amount of heat is needed to raise the temperature of a body of certain mass by \[1{}^\circ C\] and amount of heat is needed to raise the temperature of an equivalent mass of water by \[1{}^\circ C\]
From the definition of specific heat mentioned in the hint, specific heat can be given as \[\dfrac{Q}{q}\]
Now we all know that \[180\] divisions on the Fahrenheit scale correspond to \[100\] divisions of the Celsius scale.
Hence we can say that \[1{}^\circ F\] corresponds to \[{{\left( \dfrac{100}{180} \right)}^{{}^\circ }}C={{\left( \dfrac{5}{9} \right)}^{{}^\circ }}C\]
Hence the amount of heat needed to raise the temperature of the substance by one degree on the Fahrenheit will be \[\left( \dfrac{5}{9} \right)Q\]
Similarly, the amount of heat needed to raise the temperature of water by one degree on the Fahrenheit scale will be \[\left( \dfrac{5}{9} \right)q\]
Calculating the new specific heat corresponding to degree Fahrenheit, we get
specific heat \[=\dfrac{\left( \dfrac{5}{9} \right)Q}{\left( \dfrac{5}{9} \right)q}=\dfrac{Q}{q}\]
Hence we can clearly see that the specific heat remains unchanged even if the temperature is represented on the Fahrenheit scale instead of the Celsius scale.
Hence, Option (B) is the correct answer.
Note:Students often get confused with specific heat and specific heat capacity and end up doing blunders. Specific heat is a ratio whereas specific heat capacity is a measure of the amount of heat necessary to raise the temperature of one gram of a pure substance by one degree. Be mindful of the difference.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

