
An LED is forward-biased. The diode should be on, but no light is showing. A possible trouble might be :
A. The diode is open.
B. The series resistor is too small.
C. The power supply voltage is too high.
D. none of these.
Answer
502.5k+ views
Hint: A diode is a semiconductor chip that functions as a current one-way switch. It allows current to flow freely in one direction while severely restricting current flow in the other. A diode is a system that only allows current to travel in one direction. A built-in electric field is used to do this. A diode is a system that only allows current to travel in one direction. A built-in electric field is used to do this.
Complete answer:
When an electric current passes through it, a light-emitting diode emits light. It is a semiconductor-based light source. As current is passed through the LED, electrons recombine with holes, resulting in the emission of light.
It's a kind of diode that shares much of the same characteristics as a p-n junction diode. This implies that an LED causes current to flow in one direction but prevents it from flowing in the other direction. A weak coating of heavily doped semiconductor material is used to build light-emitting diodes.
In situations where traditional circuits, such as a classical diode, are used, the LEDs often have a specific voltage drop forward. The voltage drop is determined by the LED's current, the colour of the light emitted, and other factors. The voltage drop varies between 1.5V and 2.5V with currents ranging from 10 to 50 mA.
The free electrons are in the conduction band, while the holes are in the valence band. The electron from the n-type semiconductor material would overrun the p-n junction and enter with the holes in the p-type semiconductor material if the p-n junction had a forward bias.
As a result, the free electrons in the holes will be in the upper energy bands. If the voltage decreases from the conduction band to the valence band during this migration of free electrons and holes, the energy level changes. The acceleration of the electron causes a release of radiation. The emission of energy in the form of heat in standard diodes.
However, in an LED, the release of energy in the form of photons will result in the emission of light energy. The whole thing is called electroluminescence, and the diodes are called light-emitting diodes. A forward bias LED will turn on and emit light. The LED should not be affected if the series resistor is thin. The LED will shine brighter if the power supply is high, or it will burn if the power supply is short. If the LED isn't flashing, it's because it's open, which means it's not wired to the circuit.
Hence option A is correct.
Note: The forbidden energy gap determines how much energy is discharged in the form of light in LEDs. The wavelength of the light emitted may be changed. As a result, the light hue and visibility cannot be adjusted based on the wavelength. By doping the light with various impurities, the colour and wavelength of the light produced can be determined.
Complete answer:
When an electric current passes through it, a light-emitting diode emits light. It is a semiconductor-based light source. As current is passed through the LED, electrons recombine with holes, resulting in the emission of light.
It's a kind of diode that shares much of the same characteristics as a p-n junction diode. This implies that an LED causes current to flow in one direction but prevents it from flowing in the other direction. A weak coating of heavily doped semiconductor material is used to build light-emitting diodes.
In situations where traditional circuits, such as a classical diode, are used, the LEDs often have a specific voltage drop forward. The voltage drop is determined by the LED's current, the colour of the light emitted, and other factors. The voltage drop varies between 1.5V and 2.5V with currents ranging from 10 to 50 mA.
The free electrons are in the conduction band, while the holes are in the valence band. The electron from the n-type semiconductor material would overrun the p-n junction and enter with the holes in the p-type semiconductor material if the p-n junction had a forward bias.
As a result, the free electrons in the holes will be in the upper energy bands. If the voltage decreases from the conduction band to the valence band during this migration of free electrons and holes, the energy level changes. The acceleration of the electron causes a release of radiation. The emission of energy in the form of heat in standard diodes.
However, in an LED, the release of energy in the form of photons will result in the emission of light energy. The whole thing is called electroluminescence, and the diodes are called light-emitting diodes. A forward bias LED will turn on and emit light. The LED should not be affected if the series resistor is thin. The LED will shine brighter if the power supply is high, or it will burn if the power supply is short. If the LED isn't flashing, it's because it's open, which means it's not wired to the circuit.
Hence option A is correct.
Note: The forbidden energy gap determines how much energy is discharged in the form of light in LEDs. The wavelength of the light emitted may be changed. As a result, the light hue and visibility cannot be adjusted based on the wavelength. By doping the light with various impurities, the colour and wavelength of the light produced can be determined.
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