Answer
384.9k+ views
Hint: As we can all see, the force acting under a uniform magnetic field on a current-carrying wire is equal to the weight of the wire because the wire is in equilibrium and has no acceleration, so it does not move.
Formula Used: We will be using the following formula,
\[F = BiL\sin \theta \]
Where
\[F\] is the force due to the magnetic field
\[B\] is the magnitude of the magnetic field
\[i\] is the current carrying in the wire
\[L\] is the length of the wire
\[\theta \] in the angle between magnetic field and current
Complete Step-by-Step solution:
The following information is provided to us in the given question:
The mass of the wire, \[m = 200g = 0.2kg\]
The length of the wire, \[l = 15m\]
The current flowing through the wire, \[i = 2A\]
And we have to find out the magnetic field
Let us draw the stick figure of the wire given in the question and mention all the forces acting on it
Now, we can see that the direction of current is perpendicular to the magnetic field horizontally, hence the angle
$\theta = {90^\circ }$
We know that
\[F = BiL\sin \theta \]
Since, $\theta = {90^\circ }$, we have \[\sin {90^ \circ } = 1\]
So,
\[F = BiL\]
Now the weight of the wire is given by \[w = mg\]
That is \[w = 0.2 \times 9.8 N\]
According to the figure,
\[F = mg\]
Now, let us substitute the known values in the formula to get
\[BiL = mg\]
Rearranging the terms, we have
\[B = \dfrac{{mg}}{{iL}}\]
Let us now substitute the values
\[B = \dfrac{{0.2 \times 9.8}}{{2 \times 15}}\]
So, we get
\[\therefore B = 0.65 T\]
Hence, the correct option is (A.)
Note: We all learned that the left-hand rule of Fleming is used to describe the force placed at right angles to a magnetic field on a current-carrying conductor. The conductor carrying the current should be made of ferromagnetic material.
Formula Used: We will be using the following formula,
\[F = BiL\sin \theta \]
Where
\[F\] is the force due to the magnetic field
\[B\] is the magnitude of the magnetic field
\[i\] is the current carrying in the wire
\[L\] is the length of the wire
\[\theta \] in the angle between magnetic field and current
Complete Step-by-Step solution:
The following information is provided to us in the given question:
The mass of the wire, \[m = 200g = 0.2kg\]
The length of the wire, \[l = 15m\]
The current flowing through the wire, \[i = 2A\]
And we have to find out the magnetic field
Let us draw the stick figure of the wire given in the question and mention all the forces acting on it
![seo images](https://www.vedantu.com/question-sets/e06da5a0-6e42-4904-8297-ab06dcd69dbe7648949629471881895.png)
Now, we can see that the direction of current is perpendicular to the magnetic field horizontally, hence the angle
$\theta = {90^\circ }$
We know that
\[F = BiL\sin \theta \]
Since, $\theta = {90^\circ }$, we have \[\sin {90^ \circ } = 1\]
So,
\[F = BiL\]
Now the weight of the wire is given by \[w = mg\]
That is \[w = 0.2 \times 9.8 N\]
According to the figure,
\[F = mg\]
Now, let us substitute the known values in the formula to get
\[BiL = mg\]
Rearranging the terms, we have
\[B = \dfrac{{mg}}{{iL}}\]
Let us now substitute the values
\[B = \dfrac{{0.2 \times 9.8}}{{2 \times 15}}\]
So, we get
\[\therefore B = 0.65 T\]
Hence, the correct option is (A.)
Note: We all learned that the left-hand rule of Fleming is used to describe the force placed at right angles to a magnetic field on a current-carrying conductor. The conductor carrying the current should be made of ferromagnetic material.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)