Answer
415.5k+ views
Hint: In the step-up transformer the voltage increases from the primary coil to the secondary coil.
Formula used:
\[\dfrac{{{V_P}}}{{{V_S}}} = \dfrac{{{I_S}}}{{{I_P}}} = \dfrac{{{N_P}}}{{{N_S}}}\]
Where, ${N_P}$is number of turns in primary, ${N_S}$is number of turns in secondary coil, ${V_P}$ is voltage in primary coil, ${V_S}$ is voltage in secondary coil, ${I_P}$ is current in primary coil and ${I_S}$ is current in secondary coil.
Complete step-by-step answer:
Following is given in the question.
${I_P} = 4A,{I_S} = 24A,{N_P} = 330$
We have to find the number of turns in the secondary coil (${N_S}$).
Now, let us use the formula \[\dfrac{{{I_S}}}{{{I_P}}} = \dfrac{{{N_P}}}{{{N_S}}}\]to calculate${N_S}$.
We can now substitute the values in the formula.
\[\dfrac{{{I_S}}}{{{I_P}}} = \dfrac{{{N_P}}}{{{N_S}}}\]
\[\dfrac{{24}}{4} = \dfrac{{330}}{{{N_S}}}\]
After simplifying we get the following.
${N_S} = \dfrac{{4 \times 330}}{{24}} = 55$
The number of turns in the secondary coil is 55
Hence, option (E) 55 is correct.
Additional information:
An electrical device is required to transform the current from one circuit to another. The electrical device is known as a transformer.
There are two types of transformer (1) step-up transformer (2) step-down transformer.
More number of turns are present in the primary than the secondary. It converts low voltage high current power into high voltage low current power.
The step-up transformer increases the output voltage and the step-down transformer decreases the output voltage.
In the step-up transformer, the voltage binding is high. In step down transformers, the voltage binding is low.
The step-down transformer decreases the voltage from the primary to the secondary coil. It converts high voltage, low current power into low voltage high current power.
Note:
The application of the step-up transformer in India is more. In India usually, the power is generated at 11kv. For more economical reasons the power is transmitted in higher voltages and hence the step-up transformer used.
Formula used:
\[\dfrac{{{V_P}}}{{{V_S}}} = \dfrac{{{I_S}}}{{{I_P}}} = \dfrac{{{N_P}}}{{{N_S}}}\]
Where, ${N_P}$is number of turns in primary, ${N_S}$is number of turns in secondary coil, ${V_P}$ is voltage in primary coil, ${V_S}$ is voltage in secondary coil, ${I_P}$ is current in primary coil and ${I_S}$ is current in secondary coil.
Complete step-by-step answer:
Following is given in the question.
${I_P} = 4A,{I_S} = 24A,{N_P} = 330$
We have to find the number of turns in the secondary coil (${N_S}$).
Now, let us use the formula \[\dfrac{{{I_S}}}{{{I_P}}} = \dfrac{{{N_P}}}{{{N_S}}}\]to calculate${N_S}$.
We can now substitute the values in the formula.
\[\dfrac{{{I_S}}}{{{I_P}}} = \dfrac{{{N_P}}}{{{N_S}}}\]
\[\dfrac{{24}}{4} = \dfrac{{330}}{{{N_S}}}\]
After simplifying we get the following.
${N_S} = \dfrac{{4 \times 330}}{{24}} = 55$
The number of turns in the secondary coil is 55
Hence, option (E) 55 is correct.
Additional information:
An electrical device is required to transform the current from one circuit to another. The electrical device is known as a transformer.
There are two types of transformer (1) step-up transformer (2) step-down transformer.
More number of turns are present in the primary than the secondary. It converts low voltage high current power into high voltage low current power.
The step-up transformer increases the output voltage and the step-down transformer decreases the output voltage.
In the step-up transformer, the voltage binding is high. In step down transformers, the voltage binding is low.
The step-down transformer decreases the voltage from the primary to the secondary coil. It converts high voltage, low current power into low voltage high current power.
Note:
The application of the step-up transformer in India is more. In India usually, the power is generated at 11kv. For more economical reasons the power is transmitted in higher voltages and hence the step-up transformer used.
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