Answer
Verified
34.8k+ views
Hint: First use the formula
$ \Rightarrow H = mc\Delta T$ where H is heat energy, c is specific heat and $\Delta T$ is change in temperature. Then use the formula heat of solution=$\dfrac{{{\text{Heat Energy}}}}{{{\text{mass of water added}}}}$ to find the heat of solution. Change the unit from calorie into joule using the value$1{\text{cal = 4}}{\text{.186J}}$to get the answer.
Step-by-Step Solution-
Given, a coffee cup Calorimeter initially contains $125$g of water
Initial Temperature= $24.2^\circ C$
Then $10.5$ gm water is added to the water at the same temperature
Final temperature becomes= $21.1^\circ C$
We have to find the heat of solution.
We know that specific heat is the ratio of the amount of heat required to increase the temperature of an object by one degree to the amount of heat energy required to increase the temperature of water by one degree. So we can write
Heat energy= mass of object× specific heat ×change in temperature
$ \Rightarrow H = mc\Delta T$
Now here the total mass of water m= $125 + 10.5 = 135.5$
Specific heat c = $1$
$\Delta T$ = Final temperature- Initial temperature
On putting values we get,
$ \Rightarrow \Delta T = \left( {24.2 - 21.1} \right)$
On solving we get,
$ \Rightarrow \Delta T = 3.1$
On putting all these values in the formula we get,
$ \Rightarrow H = 135.5 \times 1 \times 3.1$
On solving we get,
$ \Rightarrow H = 420.05$ cal.
Then heat of solution= $\dfrac{{{\text{Heat Energy}}}}{{{\text{mass of water added}}}}$
On putting the values we get,
Heat of solution= $\dfrac{{420.05}}{{10.5}}{\text{cal}}{{\text{g}}^{{\text{ - 1}}}}$
Heat of solution= $40{\text{cal}}{{\text{g}}^{{\text{ - 1}}}}$
We know that, $1{\text{cal = 4}}{\text{.186J}}$
Then Heat of solution= $40 \times 4.186$ ${\text{J}}{{\text{g}}^{ - 1}}$
On solving we get,
Heat of solution= $167$ ${\text{J}}{{\text{g}}^{ - 1}}$
Answer-Hence the correct answer is D.
Note: Calorimeter is the device that measures the heat of chemical reaction and heat capacity. It also measures the physical changes. Coffee cup calorimeter is the simplest calorimeter in which temperatures are recorded automatically and the cup used is good insulating material with a lid to prevent the loss of heat.
$ \Rightarrow H = mc\Delta T$ where H is heat energy, c is specific heat and $\Delta T$ is change in temperature. Then use the formula heat of solution=$\dfrac{{{\text{Heat Energy}}}}{{{\text{mass of water added}}}}$ to find the heat of solution. Change the unit from calorie into joule using the value$1{\text{cal = 4}}{\text{.186J}}$to get the answer.
Step-by-Step Solution-
Given, a coffee cup Calorimeter initially contains $125$g of water
Initial Temperature= $24.2^\circ C$
Then $10.5$ gm water is added to the water at the same temperature
Final temperature becomes= $21.1^\circ C$
We have to find the heat of solution.
We know that specific heat is the ratio of the amount of heat required to increase the temperature of an object by one degree to the amount of heat energy required to increase the temperature of water by one degree. So we can write
Heat energy= mass of object× specific heat ×change in temperature
$ \Rightarrow H = mc\Delta T$
Now here the total mass of water m= $125 + 10.5 = 135.5$
Specific heat c = $1$
$\Delta T$ = Final temperature- Initial temperature
On putting values we get,
$ \Rightarrow \Delta T = \left( {24.2 - 21.1} \right)$
On solving we get,
$ \Rightarrow \Delta T = 3.1$
On putting all these values in the formula we get,
$ \Rightarrow H = 135.5 \times 1 \times 3.1$
On solving we get,
$ \Rightarrow H = 420.05$ cal.
Then heat of solution= $\dfrac{{{\text{Heat Energy}}}}{{{\text{mass of water added}}}}$
On putting the values we get,
Heat of solution= $\dfrac{{420.05}}{{10.5}}{\text{cal}}{{\text{g}}^{{\text{ - 1}}}}$
Heat of solution= $40{\text{cal}}{{\text{g}}^{{\text{ - 1}}}}$
We know that, $1{\text{cal = 4}}{\text{.186J}}$
Then Heat of solution= $40 \times 4.186$ ${\text{J}}{{\text{g}}^{ - 1}}$
On solving we get,
Heat of solution= $167$ ${\text{J}}{{\text{g}}^{ - 1}}$
Answer-Hence the correct answer is D.
Note: Calorimeter is the device that measures the heat of chemical reaction and heat capacity. It also measures the physical changes. Coffee cup calorimeter is the simplest calorimeter in which temperatures are recorded automatically and the cup used is good insulating material with a lid to prevent the loss of heat.
Recently Updated Pages
To get a maximum current in an external resistance class 1 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Let f be a twice differentiable such that fleft x rightfleft class 11 maths JEE_Main
Find the points of intersection of the tangents at class 11 maths JEE_Main
For the two circles x2+y216 and x2+y22y0 there isare class 11 maths JEE_Main
The path difference between two waves for constructive class 11 physics JEE_MAIN
Other Pages
when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Which of the following sets of displacements might class 11 physics JEE_Main
Oxidation state of S in H2S2O8 is A 6 B 7 C +8 D 0 class 12 chemistry JEE_Main
What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main
The correct IUPAC name of the given compound is A isopropylbenzene class 11 chemistry JEE_Main