Answer
Verified
35.1k+ views
Hint- Probability is the ratio of favourable number of outcomes and total number of outcomes.
First bag contains 3 white and 2 black balls.
Second bag contains 2 white and 4 black balls.
Consider the following events which is given
${A_1} = $Selecting first bag
${A_2} = $Selecting second bag
$x = $Ball drawn is white
Then, Probability of selecting the bag\[{\text{ = }}\dfrac{{{\text{Favorable bags}}}}{{{\text{total bags}}}}\]
\[ \Rightarrow P\left( {{A_1}} \right) = P\left( {{A_2}} \right) = \dfrac{1}{2}\]
$ \Rightarrow $Probability of getting white ball from first bag \[{\text{P}}\left( {\dfrac{x}{{{A_1}}}} \right){\text{ = }}\dfrac{{{\text{Favorable balls}}}}{{{\text{total balls}}}} = \dfrac{3}{5}\]
$ \Rightarrow $ Probability of getting white ball from second bag \[{\text{P}}\left( {\dfrac{x}{{{A_2}}}} \right){\text{ = }}\dfrac{{{\text{Favorable balls}}}}{{{\text{total balls}}}} = \dfrac{2}{6} = \dfrac{1}{3}\]
$ \Rightarrow $Probability that the ball drawn is white is \[{\text{P}}\left( x \right){\text{ = }}P\left( {{A_1}} \right){\text{ P}}\left( {\dfrac{x}{{{A_1}}}} \right) + P\left( {{A_2}} \right){\text{P}}\left( {\dfrac{x}{{{A_2}}}} \right)...............\left( 1 \right)\]
\[
{\text{P}}\left( x \right) = \dfrac{1}{2} \times \dfrac{3}{5} + \dfrac{1}{2} \times \dfrac{1}{3} \\
{\text{P}}\left( x \right) = \dfrac{3}{{10}} + \dfrac{1}{6} = \dfrac{7}{{15}} \\
\]
So, this is the required probability.
Note-In such types of questions first calculate the probability of selecting a bag and probability of getting white ball drawn from each bag using the formula which is stated above, then apply the formula which is written in equation (1) to get the required probability.
First bag contains 3 white and 2 black balls.
Second bag contains 2 white and 4 black balls.
Consider the following events which is given
${A_1} = $Selecting first bag
${A_2} = $Selecting second bag
$x = $Ball drawn is white
Then, Probability of selecting the bag\[{\text{ = }}\dfrac{{{\text{Favorable bags}}}}{{{\text{total bags}}}}\]
\[ \Rightarrow P\left( {{A_1}} \right) = P\left( {{A_2}} \right) = \dfrac{1}{2}\]
$ \Rightarrow $Probability of getting white ball from first bag \[{\text{P}}\left( {\dfrac{x}{{{A_1}}}} \right){\text{ = }}\dfrac{{{\text{Favorable balls}}}}{{{\text{total balls}}}} = \dfrac{3}{5}\]
$ \Rightarrow $ Probability of getting white ball from second bag \[{\text{P}}\left( {\dfrac{x}{{{A_2}}}} \right){\text{ = }}\dfrac{{{\text{Favorable balls}}}}{{{\text{total balls}}}} = \dfrac{2}{6} = \dfrac{1}{3}\]
$ \Rightarrow $Probability that the ball drawn is white is \[{\text{P}}\left( x \right){\text{ = }}P\left( {{A_1}} \right){\text{ P}}\left( {\dfrac{x}{{{A_1}}}} \right) + P\left( {{A_2}} \right){\text{P}}\left( {\dfrac{x}{{{A_2}}}} \right)...............\left( 1 \right)\]
\[
{\text{P}}\left( x \right) = \dfrac{1}{2} \times \dfrac{3}{5} + \dfrac{1}{2} \times \dfrac{1}{3} \\
{\text{P}}\left( x \right) = \dfrac{3}{{10}} + \dfrac{1}{6} = \dfrac{7}{{15}} \\
\]
So, this is the required probability.
Note-In such types of questions first calculate the probability of selecting a bag and probability of getting white ball drawn from each bag using the formula which is stated above, then apply the formula which is written in equation (1) to get the required probability.
Recently Updated Pages
To get a maximum current in an external resistance class 1 physics JEE_Main
f a body travels with constant acceleration which of class 1 physics JEE_Main
If the beams of electrons and protons move parallel class 1 physics JEE_Main
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
Let f be a twice differentiable such that fleft x rightfleft class 11 maths JEE_Main
Find the points of intersection of the tangents at class 11 maths JEE_Main
Other Pages
Oxidation state of S in H2S2O8 is A 6 B 7 C +8 D 0 class 12 chemistry JEE_Main
The mole fraction of the solute in a 1 molal aqueous class 11 chemistry JEE_Main
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
Electric field due to uniformly charged sphere class 12 physics JEE_Main
Explain the construction and working of a GeigerMuller class 12 physics JEE_Main
Dissolving 120g of urea molwt60 in 1000g of water gave class 11 chemistry JEE_Main