
Which of the following substances are soluble in concentrated $HN{O_3}$ ?
(A) $BaS{O_4}$
(B) $CuS$
(C) $PbS$
(D) $HgS$
Answer
219.9k+ views
Hint: $HN{O_3}$ , often known as nitric acid, is a very corrosive mineral acid. As it interacts with various chemicals, it displays various traits. Depending on the quantity of $HN{O_3}$ , several products can be produced in reactions involving this compound. When nitric acid concentrations are low, it behaves similarly to other common acids.
Complete Step by Step Solution:
A nitrogen oxoacid with the formula $HN{O_3}$ is nitric acid, in which the nitrogen atom is linked to a hydroxyl group and the other two oxygen atoms by analogous bonds. It serves as a reagent and a protic solvent. It is a nitrate's conjugate acid.
Citrus juice $\left( {HN{O_3}} \right)$ , a colourless liquid used in the production of nitrates and nitro compounds for fertilisers, intermediates in dyeing processes, explosives, and several other organic chemicals. Chemical pneumonitis and chronic bronchitis are both possible side effects of prolonged vapour exposure.
Now we know that $HN{O_3}$ dissociates into ${H^ + }$ and $N{O_3}^ - $ ions, and $BaS{O_4}$ dissociates into $B{a^{2 + }}$ and $S{O_4}^{2 - }$ . If we look at the given question we will find that because the ${H^ + }$ ions of the acid cannot dissolve the $S{O_4}^{2 - }$ ions from barium sulphate, $BaS{O_4}$ is insoluble in concentrated $HN{O_3}$ .
Whereas $CuS$ is soluble in concentrated $HN{O_3}$ , leaving a white precipitate of sulphur.
\[CuS + 8HN{O_3}\,\, \to \,\,CuS{O_4} + 8N{O_2} + 4{H_2}O\]
$PbS$ is also soluble in concentrated $HN{O_3}$ . The reaction is as follows:
\[3PbS + 8HN{O_3}\,\, \to \,\,3PbS{O_4} + 8NO + 4{H_2}O\]
Similary $HgS$ is also soluble in concentrated $HN{O_3}$ .
Hence, option B., C. and D. are correct.
Note: For answering such questions one must have knowledge of properties of various chemical compounds and how they react with other chemical compounds specially some a few main acids and bases. If we include any chemical reaction in our solution then balancing those equations is important.
Complete Step by Step Solution:
A nitrogen oxoacid with the formula $HN{O_3}$ is nitric acid, in which the nitrogen atom is linked to a hydroxyl group and the other two oxygen atoms by analogous bonds. It serves as a reagent and a protic solvent. It is a nitrate's conjugate acid.
Citrus juice $\left( {HN{O_3}} \right)$ , a colourless liquid used in the production of nitrates and nitro compounds for fertilisers, intermediates in dyeing processes, explosives, and several other organic chemicals. Chemical pneumonitis and chronic bronchitis are both possible side effects of prolonged vapour exposure.
Now we know that $HN{O_3}$ dissociates into ${H^ + }$ and $N{O_3}^ - $ ions, and $BaS{O_4}$ dissociates into $B{a^{2 + }}$ and $S{O_4}^{2 - }$ . If we look at the given question we will find that because the ${H^ + }$ ions of the acid cannot dissolve the $S{O_4}^{2 - }$ ions from barium sulphate, $BaS{O_4}$ is insoluble in concentrated $HN{O_3}$ .
Whereas $CuS$ is soluble in concentrated $HN{O_3}$ , leaving a white precipitate of sulphur.
\[CuS + 8HN{O_3}\,\, \to \,\,CuS{O_4} + 8N{O_2} + 4{H_2}O\]
$PbS$ is also soluble in concentrated $HN{O_3}$ . The reaction is as follows:
\[3PbS + 8HN{O_3}\,\, \to \,\,3PbS{O_4} + 8NO + 4{H_2}O\]
Similary $HgS$ is also soluble in concentrated $HN{O_3}$ .
Hence, option B., C. and D. are correct.
Note: For answering such questions one must have knowledge of properties of various chemical compounds and how they react with other chemical compounds specially some a few main acids and bases. If we include any chemical reaction in our solution then balancing those equations is important.
Recently Updated Pages
Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

States of Matter Chapter For JEE Main Chemistry

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Centrifugal Force in Physics

Other Pages
Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

The D and F Block Elements Class 12 Chemistry Chapter 4 CBSE Notes - 2025-26

NCERT Solutions for Class 12 Chemistry Chapter Chapter 7 Alcohol Phenol and Ether

NCERT Solutions ForClass 12 Chemistry Chapter Chapter 8 Aldehydes Ketones And Carboxylic Acids

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

