
Which of the following options gives ethyl benzene with phenyl methyl ketone?
A. \[Zn - Hg + HCl\]
B. \[LiAl{H_4}\]
C. \[KMn{O_4}\]
D. None of the above
Answer
162.9k+ views
Hint: Phenyl Methyl ketone (Acetophenone) is the organic compound with the formula \[{C_6}{H_5}CC{H_3}\]. It is known as the simplest aromatic ketone. It is a colourless and viscous liquid and is useful in making resins and fragrances as a precursor. The ketone group of the Phenyl methyl ketone compound is being reduced in this reaction.
Complete Step by Step Solution:
For reducing aldehydes or ketones, zinc amalgam along with HCl is used. This reaction which reduces ketones or aldehydes is also known as Clemmensen's reduction reaction. It is named after the famous Danish chemist, Erik Christian Clemmensen. The reaction is carried out below:

Image: Chemical Reaction
Thus, the correct answer to this question will be, option (A).
Additional Information:
Alkane from alkenyl chloride (halide) can be prepared from any organic compound which is transformed into alkenyl halide. This reaction is widely used to convert the carbonyl group into a methyl group. Preparation of polycyclic aromatics and aromatics containing the unbranched sides of the hydrocarbon chain. The reaction helps to reduce the aliphatic and the mixed aliphatic-aromatic carbonyl compounds. The Clemmensen reduction is most widely used to transform acyl benzene (from acylation by Friedel-Crafts) to alkylbenzene.
Note: The mechanism of the Clemmensen reduction reaction is not well known. Still, there are two proposals for its mechanism:
1) Carbanionic Mechanism: In the Carbanionic mechanism, zinc attacks directly the protonated carbon.
2) Carbenoid Mechanism: It's a radical process that reduces the happenings on the metal surface of zinc. The reaction of the carbenoid mechanism always takes place at the surface of the zinc catalyst.
Complete Step by Step Solution:
For reducing aldehydes or ketones, zinc amalgam along with HCl is used. This reaction which reduces ketones or aldehydes is also known as Clemmensen's reduction reaction. It is named after the famous Danish chemist, Erik Christian Clemmensen. The reaction is carried out below:

Image: Chemical Reaction
Thus, the correct answer to this question will be, option (A).
Additional Information:
Alkane from alkenyl chloride (halide) can be prepared from any organic compound which is transformed into alkenyl halide. This reaction is widely used to convert the carbonyl group into a methyl group. Preparation of polycyclic aromatics and aromatics containing the unbranched sides of the hydrocarbon chain. The reaction helps to reduce the aliphatic and the mixed aliphatic-aromatic carbonyl compounds. The Clemmensen reduction is most widely used to transform acyl benzene (from acylation by Friedel-Crafts) to alkylbenzene.
Note: The mechanism of the Clemmensen reduction reaction is not well known. Still, there are two proposals for its mechanism:
1) Carbanionic Mechanism: In the Carbanionic mechanism, zinc attacks directly the protonated carbon.
2) Carbenoid Mechanism: It's a radical process that reduces the happenings on the metal surface of zinc. The reaction of the carbenoid mechanism always takes place at the surface of the zinc catalyst.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main Mock Test Series Class 12 Chemistry for FREE

Classification of Drugs Based on Pharmacological Effect, Drug Action

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
