Water rises to a height $h$ in capillary tube. If the length of capillary tube above the surface of water is made less than $h$ then:
(A) Water does not rise at all
(B) Water rises up to the tip of capillary tube and then starts overflowing like a fountain
(C) water rises up to the top of capillary tube and stays there without overflowing
(D) Water rises up to a point a little below the top and stays there
Answer
301.2k+ views
Hint: The rise in level of water is seen due to the adhesion of water to the walls which causes an upwards force on the liquid at the edges and results in a meniscus which turns upwards. For a given system, the product between inner radius and the rise in height water remains constant. In simple terms, we can say that height is inversely proportional to the inner radius of the capillary tube.
Complete step by step answer : The same force that pulls the water along the inside of the capillary tube also holds it there when it reaches the end. This force doesn’t just pull upward, it pulls the water along the glass. At a certain height, the weight of the water column balances this pull. In that case the pull is upward since there is water below but not above.
The rise in height of water level is given as: \[\]
$h = \dfrac{{2S}}{{\rho gR}}$
Here, $h$ is the rise in the level
$\rho $ is the density of water
$S$ is the surface tension
$g$ is the acceleration due to gravity;
$R$ is the inner radius.
Now, for a given system, we have
$hR = \dfrac{{2S}}{{\rho g}}$
As density, surface tension and acceleration due to gravity will remain constant therefore, the product of radius and height must also remain constant.
Now, as the height decreases, the radius changes and water reach the same level and stops. There is no overflow.
Therefore, option C is the correct option.
Note: The liquid rises due to various forces such as adhesion, cohesion and surface tension. The contact angle is also taken into account. The product of radius and the rise in height remains constant for a given system. When the length of the capillary tube changes, the radius changes in such a manner so that there is no overflow and the product of radius and rise in height remains constant.
Complete step by step answer : The same force that pulls the water along the inside of the capillary tube also holds it there when it reaches the end. This force doesn’t just pull upward, it pulls the water along the glass. At a certain height, the weight of the water column balances this pull. In that case the pull is upward since there is water below but not above.
The rise in height of water level is given as: \[\]
$h = \dfrac{{2S}}{{\rho gR}}$
Here, $h$ is the rise in the level
$\rho $ is the density of water
$S$ is the surface tension
$g$ is the acceleration due to gravity;
$R$ is the inner radius.
Now, for a given system, we have
$hR = \dfrac{{2S}}{{\rho g}}$
As density, surface tension and acceleration due to gravity will remain constant therefore, the product of radius and height must also remain constant.
Now, as the height decreases, the radius changes and water reach the same level and stops. There is no overflow.
Therefore, option C is the correct option.
Note: The liquid rises due to various forces such as adhesion, cohesion and surface tension. The contact angle is also taken into account. The product of radius and the rise in height remains constant for a given system. When the length of the capillary tube changes, the radius changes in such a manner so that there is no overflow and the product of radius and rise in height remains constant.
Recently Updated Pages
Four persons A B C and D initially at the corners of class 11 physics JEE_Main

What is the difference between Conduction and conv class 11 physics JEE_Main

Moment of inertia of solid sphere about its diameter class 11 physics JEE_Main

If a piece of ice floating on the surface of water class 11 physics JEE_Main

At what temperature speed of sound in air will be doubled class 11 physics JEE_Main

A closed organ pipe and an open organ pipe are tuned class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Understanding Uniform Acceleration in Physics

Other Pages
CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2026-27 Free PDF Download (Login Required)

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2026-27 Free PDF Download (Sign-in Required)

CBSE Notes Class 11 Physics Chapter 2 - Motion in a Straight Line - 2026-27 PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 3 Motion In A Plane - 2026-27 Free PDF Download (Sign-in Required)

