Answer
Verified
64.8k+ views
Hint: When two solutions of the same compound but of different molarity and volumes are added to obtain a new solution, the formula to be applied is:
${M_1}{V_1} + {M_2}{V_2} = MV$
Complete step by step solution:
-Here in the question we can see that two solutions of HCl of different molarity and volume are mixed to form a new solution.
For such mixtures the formula used is:
${M_1}$${V_1}$ $+$ ${M_2}$${V_2}$ $= MV$ ------------(1)
Where, ${M_1}$, ${M_2}$, ${V_1}$ and ${V_2}$ are the molarity and volume of the solutions being mixed. And M and V are the molarity and volume of the final solution being formed.
-The question gives us the following values:
${M_1}$ $= 6M$
${M_2}$ $= 3M$
${V_1}$ $= 250 ml$
${V_2}$ $= 650 ml$
$M =$ $3M$ and $V =$ ?
Putting these above given values in equation (1):
$\implies \left( {6 \times 250} \right) + \left( {3 \times 650} \right) = 3 \times V$
$\implies 1500 + 1950 = 3 \times V$
$\implies 3450 = 3 \times V$
$\implies V = \dfrac{{3450}}{3}$
$\implies V =$ $1150 ml$
Hence, the total volume of the final solution is 1150 ml.
-The volume of the solution initially mixed = ${V_1} + {V_2}$
$\implies$ $250 + 650 = 900ml$
-Now we need to calculate the volume of water we need to add to the initial solution to make the final solution. We can calculate this water to be added by subtracting the initial volume of solution from the final volume of solution.
We know that initial volume is: ${V_{initial}}$ = 900 ml and ${V_{final}}$ = 1150 ml
So, the volume of water to be added = ${V_{final}} - {V_{initial}}$
$\implies$ $1150 - 900$
$\implies$ $250 ml$
We can finally say that the volume of water to be added to obtain a 3M final solution is 250 ml.
Hence, the correct option will be: (D) 250 ml.
Note: Remember we need to calculate the volume of water to be added to make the solution 3M so we need to subtract initial volume from the final volume and obtain the answer.
${M_1}{V_1} + {M_2}{V_2} = MV$
Complete step by step solution:
-Here in the question we can see that two solutions of HCl of different molarity and volume are mixed to form a new solution.
For such mixtures the formula used is:
${M_1}$${V_1}$ $+$ ${M_2}$${V_2}$ $= MV$ ------------(1)
Where, ${M_1}$, ${M_2}$, ${V_1}$ and ${V_2}$ are the molarity and volume of the solutions being mixed. And M and V are the molarity and volume of the final solution being formed.
-The question gives us the following values:
${M_1}$ $= 6M$
${M_2}$ $= 3M$
${V_1}$ $= 250 ml$
${V_2}$ $= 650 ml$
$M =$ $3M$ and $V =$ ?
Putting these above given values in equation (1):
$\implies \left( {6 \times 250} \right) + \left( {3 \times 650} \right) = 3 \times V$
$\implies 1500 + 1950 = 3 \times V$
$\implies 3450 = 3 \times V$
$\implies V = \dfrac{{3450}}{3}$
$\implies V =$ $1150 ml$
Hence, the total volume of the final solution is 1150 ml.
-The volume of the solution initially mixed = ${V_1} + {V_2}$
$\implies$ $250 + 650 = 900ml$
-Now we need to calculate the volume of water we need to add to the initial solution to make the final solution. We can calculate this water to be added by subtracting the initial volume of solution from the final volume of solution.
We know that initial volume is: ${V_{initial}}$ = 900 ml and ${V_{final}}$ = 1150 ml
So, the volume of water to be added = ${V_{final}} - {V_{initial}}$
$\implies$ $1150 - 900$
$\implies$ $250 ml$
We can finally say that the volume of water to be added to obtain a 3M final solution is 250 ml.
Hence, the correct option will be: (D) 250 ml.
Note: Remember we need to calculate the volume of water to be added to make the solution 3M so we need to subtract initial volume from the final volume and obtain the answer.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
Electric field due to uniformly charged sphere class 12 physics JEE_Main
According to classical free electron theory A There class 11 physics JEE_Main
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main