
Two sound sources \[{S_1}\] and \[{S_2}\] emit pure sinusoidal waves in phase. If the speed of sound is 330 m/s, then for what frequencies does constructive interference occur at P?

A. 500 Hz
B. 1000 Hz
C. 1200 Hz
D. 1500 Hz
Answer
232.8k+ views
Hint:To solve this question we have to use the relationship between the frequencies for constructive interference and the path difference of two given sound sources. Path difference can be obtained by using Pythagoras theorem.
Formula used:
Path difference for constructive interference is given as,
\[\Delta x = n\lambda = n\left( {\dfrac{v}{f}} \right)\]
Where n is an integer, \[\lambda \] is the wavelength, v is the speed of sound and f is the frequency.
Complete step by step solution:
Given the speed of sound v = 330 m/s
If the line PO is perpendicular to the line joining the two sound sources \[{S_1}\]and\[{S_2}\].
Separation between the two sound sources \[{S_1}\] and \[{S_2}\], \[{S_1}{S_2}\]= 4.68M

Image: Separation between the two sound sources \[{S_1}\] and \[{S_2}\].
From the given data, we have
\[{S_1}P = \sqrt {{3^2} + {4^2}} = 5\]
And,
\[{S_2}P = \sqrt {{4^2} + {{1.68}^2}} = 4.338\]
As we know that Path difference,
\[\Delta x = \left| {{S_1}P - {S_2}P} \right| \\ \]
\[\Rightarrow \Delta x = 5 - 4.338 \approx 0.66 \\ \]
Also, we know that for constructive interference,
\[\Delta x = n\lambda = n\left( {\dfrac{v}{f}} \right)\]
where n = 1,2, 3…...
Now the frequency is given as,
\[f = \dfrac{{nv}}{{\Delta x}} \\ \]
\[\Rightarrow f = \dfrac{{n \times 330}}{{0.66}} \\ \]
\[\Rightarrow f = 500n{\rm{ Hz}}\]
For n = 0, frequency, f = 0
For n = 1, frequency, f = 500 Hz
For n = 2, frequency, f = 1000 Hz
For n = 3, frequency, f = 1500 Hz
and so on.
Therefore, for the frequencies constructive interference occurs at P is 500 Hz, 100 Hz, 1500 Hz and so on.
Hence option A, B and D is the correct answer.
Note: The difference in distance travelled by the two waves is defined as the one full wavelength or the path difference is \[1\lambda \]. When the path difference (\[\Delta x\]) is one full wavelength then a crest meets a crest and constructive interference occurs.
Formula used:
Path difference for constructive interference is given as,
\[\Delta x = n\lambda = n\left( {\dfrac{v}{f}} \right)\]
Where n is an integer, \[\lambda \] is the wavelength, v is the speed of sound and f is the frequency.
Complete step by step solution:
Given the speed of sound v = 330 m/s
If the line PO is perpendicular to the line joining the two sound sources \[{S_1}\]and\[{S_2}\].
Separation between the two sound sources \[{S_1}\] and \[{S_2}\], \[{S_1}{S_2}\]= 4.68M

Image: Separation between the two sound sources \[{S_1}\] and \[{S_2}\].
From the given data, we have
\[{S_1}P = \sqrt {{3^2} + {4^2}} = 5\]
And,
\[{S_2}P = \sqrt {{4^2} + {{1.68}^2}} = 4.338\]
As we know that Path difference,
\[\Delta x = \left| {{S_1}P - {S_2}P} \right| \\ \]
\[\Rightarrow \Delta x = 5 - 4.338 \approx 0.66 \\ \]
Also, we know that for constructive interference,
\[\Delta x = n\lambda = n\left( {\dfrac{v}{f}} \right)\]
where n = 1,2, 3…...
Now the frequency is given as,
\[f = \dfrac{{nv}}{{\Delta x}} \\ \]
\[\Rightarrow f = \dfrac{{n \times 330}}{{0.66}} \\ \]
\[\Rightarrow f = 500n{\rm{ Hz}}\]
For n = 0, frequency, f = 0
For n = 1, frequency, f = 500 Hz
For n = 2, frequency, f = 1000 Hz
For n = 3, frequency, f = 1500 Hz
and so on.
Therefore, for the frequencies constructive interference occurs at P is 500 Hz, 100 Hz, 1500 Hz and so on.
Hence option A, B and D is the correct answer.
Note: The difference in distance travelled by the two waves is defined as the one full wavelength or the path difference is \[1\lambda \]. When the path difference (\[\Delta x\]) is one full wavelength then a crest meets a crest and constructive interference occurs.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Uniform Acceleration in Physics

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

Understanding Electromagnetic Waves and Their Importance

