Two particles execute S.H.M of same amplitude and frequency along the same straight line from the same mean position. They cross one another without collision, when going in the opposite direction, each time their displacement is half of their amplitude. The phase-difference between them is:
A) ${0^o}$
B) ${120^o}$
C) ${180^o}$
D) ${135^o}$
Answer
249.3k+ views
Hint: Here it is given that two particles execute S.H.M and their amplitude and frequency are also the same. So, first assume such particles executing S.H.M in the form of sine and cosine waves. After assuming the motion of the particles focus on the point that each time their displacement is half of their amplitudes. This will help you determine the initial phase and then as they move in the opposite direction after collision so accordingly the phase difference would also be calculated.
Complete step by step solution:
Here it is given in the question that these two particles execute S.H.M and both the particles have same amplitude and frequency, so the equation would be given by,
${x_1} = {x_m}\cos \omega t$
${x_2} = {x_m}\cos (\omega t + \phi )$
It is given that these two particles cross paths with each other. Also, their displacement is half of their amplitudes, so here ${x_1} = \dfrac{{{x_m}}}{2}$
As, ${x_1} = {x_m}\cos \omega t$
So, equating the both expressions of ${x_1}$ we have,
$\dfrac{{{x_m}}}{2} = {x_m}\cos \omega t$
After cancelling ${x_m}$ from both the sides we have,
$\cos \omega t = \dfrac{1}{2}$
So, we have $\omega t = \dfrac{\pi }{3}$
Now similarly for ${x_2}$ we are given that they are moving in different directions after collision, so the closest value of $\omega t + \phi = \dfrac{{2\pi }}{3}$
Putting the value of $\omega t = \dfrac{\pi }{3}$
We have,
$\dfrac{\pi }{3} + \phi = \dfrac{{2\pi }}{3}$
On solving for the value of $\phi $ we have,
$\phi = \dfrac{\pi }{3}$
In degrees this angle would be equal to ${120^o}$ .
So here the correct answer is option B that is ${120^o}$.
Note: It is important to note the concept of Phase Difference. It is used to describe the difference in degrees or difference in radians when two or more alternating quantities reach their maximum or zero value. In other words phase difference is the lateral difference between two or more waveforms along a common axis and sinusoidal waveforms of the same frequency can have a phase difference.
Complete step by step solution:
Here it is given in the question that these two particles execute S.H.M and both the particles have same amplitude and frequency, so the equation would be given by,
${x_1} = {x_m}\cos \omega t$
${x_2} = {x_m}\cos (\omega t + \phi )$
It is given that these two particles cross paths with each other. Also, their displacement is half of their amplitudes, so here ${x_1} = \dfrac{{{x_m}}}{2}$
As, ${x_1} = {x_m}\cos \omega t$
So, equating the both expressions of ${x_1}$ we have,
$\dfrac{{{x_m}}}{2} = {x_m}\cos \omega t$
After cancelling ${x_m}$ from both the sides we have,
$\cos \omega t = \dfrac{1}{2}$
So, we have $\omega t = \dfrac{\pi }{3}$
Now similarly for ${x_2}$ we are given that they are moving in different directions after collision, so the closest value of $\omega t + \phi = \dfrac{{2\pi }}{3}$
Putting the value of $\omega t = \dfrac{\pi }{3}$
We have,
$\dfrac{\pi }{3} + \phi = \dfrac{{2\pi }}{3}$
On solving for the value of $\phi $ we have,
$\phi = \dfrac{\pi }{3}$
In degrees this angle would be equal to ${120^o}$ .
So here the correct answer is option B that is ${120^o}$.
Note: It is important to note the concept of Phase Difference. It is used to describe the difference in degrees or difference in radians when two or more alternating quantities reach their maximum or zero value. In other words phase difference is the lateral difference between two or more waveforms along a common axis and sinusoidal waveforms of the same frequency can have a phase difference.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Instantaneous Velocity Explained: Formula, Examples & Graphs

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Hybridisation in Chemistry – Concept, Types & Applications

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2025-26

CBSE Notes Class 11 Physics Chapter 4 - Laws of Motion - 2025-26

