Two cars A and B moving with velocity $36 km/h$ and $54km/h$ moving along a straight line the car B follow car A. The length of each car is $5m$ . The time taken by car B to cross car A and also find distance travelled by both cars during this time?
Answer
281.7k+ views
Hint: For solving this question we have to calculate the time when car B crosses car A. And we have to calculate the distance at the crossing time which is the final speed $ \times $ time. For calculating the time, we know distance upon speed which means length of car A $ + $ car B and then divide by relative velocity. For that we have different velocity for both the car and for that we have to find out first relative velocity. Knowing all these values and after substituting we can get the required answer.
Complete step by step solution:
Distance between the end of car B and the front point of car A is $10m$.
Now,
${v_{relative}} = 54 - 36$
We get $18km/h $
Now, we have to calculate time taken to travel 10m is $t = \dfrac{{10 \times 10}}{{18}}$
Now converting kilometres to meters, we get $t = \dfrac{5}{9} \times {10^{ - 3}}$
Now, we have to find out the total distance travelled by car B over car A.
That is, $t = \dfrac{5}{9} \times {10^{ - 3}} \times 54 \times 1000$
$\therefore t = 30m$
So, the time taken by car b to cross car A is $30m$.
So, The correct answer is $30m$.
Note: For solving this question we have to find out the total time taken by car B while crossing Car A. For solving this question we have to calculate the distance between both cars and how much take it takes. Since, we know distance can be defined as the length of the space between two points this is known as distance. We have to calculate relative velocity. By substituting all these values, we can get the correct answer. So, these are some important points.
Complete step by step solution:
Distance between the end of car B and the front point of car A is $10m$.
Now,
${v_{relative}} = 54 - 36$
We get $18km/h $
Now, we have to calculate time taken to travel 10m is $t = \dfrac{{10 \times 10}}{{18}}$
Now converting kilometres to meters, we get $t = \dfrac{5}{9} \times {10^{ - 3}}$
Now, we have to find out the total distance travelled by car B over car A.
That is, $t = \dfrac{5}{9} \times {10^{ - 3}} \times 54 \times 1000$
$\therefore t = 30m$
So, the time taken by car b to cross car A is $30m$.
So, The correct answer is $30m$.
Note: For solving this question we have to find out the total time taken by car B while crossing Car A. For solving this question we have to calculate the distance between both cars and how much take it takes. Since, we know distance can be defined as the length of the space between two points this is known as distance. We have to calculate relative velocity. By substituting all these values, we can get the correct answer. So, these are some important points.
Recently Updated Pages
How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

Mass vs Weight: Key Differences Explained for Students

JEE Main 2025-26 Mock Test: Binomial Theorem & Quick Practice

Properties of Solids and Liquids Mock Test 2025

JEE Main Mock Test 2025-26: Principles Related To Practical

Trending doubts
Understanding Atomic Structure for Beginners

Understanding Instantaneous Velocity

Understanding Uniform Acceleration in Physics

Understanding the Angle of Deviation in a Prism

How Does Fusion Reaction Happen Inside the Sun?

Find the frictional force between the two blocks in class 11 physics JEE_MAIN

Other Pages
JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

NCERT Solutions For Class 11 Physics In Hindi Chapter 1 Physical World - 2026-27

CBSE Notes Class 11 Physics Chapter 9 - Mechanical Properties of Fluids - 2026-27

JEE Advanced 2026 Revision Notes for Vectors

CBSE Notes Class 11 Physics Chapter 5 - Work Energy and Power - 2026-27

JEE Advanced 2026 Notes

