Two cars A and B moving with velocity $36 km/h$ and $54km/h$ moving along a straight line the car B follow car A. The length of each car is $5m$ . The time taken by car B to cross car A and also find distance travelled by both cars during this time?
Answer
283.8k+ views
Hint: For solving this question we have to calculate the time when car B crosses car A. And we have to calculate the distance at the crossing time which is the final speed $ \times $ time. For calculating the time, we know distance upon speed which means length of car A $ + $ car B and then divide by relative velocity. For that we have different velocity for both the car and for that we have to find out first relative velocity. Knowing all these values and after substituting we can get the required answer.
Complete step by step solution:
Distance between the end of car B and the front point of car A is $10m$.
Now,
${v_{relative}} = 54 - 36$
We get $18km/h $
Now, we have to calculate time taken to travel 10m is $t = \dfrac{{10 \times 10}}{{18}}$
Now converting kilometres to meters, we get $t = \dfrac{5}{9} \times {10^{ - 3}}$
Now, we have to find out the total distance travelled by car B over car A.
That is, $t = \dfrac{5}{9} \times {10^{ - 3}} \times 54 \times 1000$
$\therefore t = 30m$
So, the time taken by car b to cross car A is $30m$.
So, The correct answer is $30m$.
Note: For solving this question we have to find out the total time taken by car B while crossing Car A. For solving this question we have to calculate the distance between both cars and how much take it takes. Since, we know distance can be defined as the length of the space between two points this is known as distance. We have to calculate relative velocity. By substituting all these values, we can get the correct answer. So, these are some important points.
Complete step by step solution:
Distance between the end of car B and the front point of car A is $10m$.
Now,
${v_{relative}} = 54 - 36$
We get $18km/h $
Now, we have to calculate time taken to travel 10m is $t = \dfrac{{10 \times 10}}{{18}}$
Now converting kilometres to meters, we get $t = \dfrac{5}{9} \times {10^{ - 3}}$
Now, we have to find out the total distance travelled by car B over car A.
That is, $t = \dfrac{5}{9} \times {10^{ - 3}} \times 54 \times 1000$
$\therefore t = 30m$
So, the time taken by car b to cross car A is $30m$.
So, The correct answer is $30m$.
Note: For solving this question we have to find out the total time taken by car B while crossing Car A. For solving this question we have to calculate the distance between both cars and how much take it takes. Since, we know distance can be defined as the length of the space between two points this is known as distance. We have to calculate relative velocity. By substituting all these values, we can get the correct answer. So, these are some important points.
Recently Updated Pages
How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

Mass vs Weight: Key Differences Explained for Students

Uniform Acceleration Explained: Formula, Examples & Graphs

JEE Main 2025-26 Mock Test: Binomial Theorem & Quick Practice

Properties of Solids and Liquids Mock Test 2025

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Derivation of Equation of Trajectory Explained for Students

Electron Gain Enthalpy and Electron Affinity Explained

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2026-27 Free PDF Download (Login Required)

NCERT Solutions For Class 11 Physics Chapter 2 Motion In A Straight Line - 2026-27 Free PDF Download (Login Required)

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2026-27

CBSE Notes Class 11 Physics Chapter 2 - Motion in a Straight Line - 2026-27

