
Twists of suspension fibre should be removed in vibration magnetometer so that
A. Time period be less
B. Time period be more
C. Magnet may vibrate freely
D. Cannot be said with certainty
Answer
161.1k+ views
Hint: Magnetic moments and magnetic fields are compared using a vibration magnetometer. The basis for this device's operation is the fact that anytime a freely suspended magnet in a uniform magnetic field is moved from its equilibrium point, it begins to vibrate about the mean location. In a nutshell, torque operating on the bar magnet is the basis for how vibration magnetometers operate.
Formula used:
The expression of time period of a magnet in a vibration magnetometer is,
$\mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{I}}{\mathrm{MB}}}$
Here, $I$ is the moment of inertia, $M$ is the magnetic moment and $B$ is the magnetic field.
Complete step by step solution:
The amount of time it takes for any string element to complete one oscillation is known as the wave's time period.
Magnet is suspended like a free body in a vibration magnetometer.
$\mathrm{T}=2 \pi \sqrt{\dfrac{1}{\mathrm{~g}}}$
Twist causes a reduction in length and from the above expression we can say that if length is reduced then the time period will decrease. Therefore, if the twists in the suspension fibre are removed, the time period increases.
Hence,the correct answer is option B.
Additional information: A bar magnet held freely in a uniform magnetic field begins to move in a straightforward harmonic manner about the equilibrium position when it is moved from that location. The sign indicating that the torque works in the direction of decreasing $\tau=-M B_{H} \theta$ is $\tau=-m B_{H}(2 \ell \sin \theta)=-M B_{H} \sin \theta$ .If $\tau=-M B_{H} \theta$ is small , then$\tau=-M B_{H} \theta$
Note: It is a tool for measuring the horizontal component of the earth's magnetic field as well as comparing the magnetic moments of two bar magnets and the horizontal components of the earth's magnetic field at two locations.
Formula used:
The expression of time period of a magnet in a vibration magnetometer is,
$\mathrm{T}=2 \pi \sqrt{\dfrac{\mathrm{I}}{\mathrm{MB}}}$
Here, $I$ is the moment of inertia, $M$ is the magnetic moment and $B$ is the magnetic field.
Complete step by step solution:
The amount of time it takes for any string element to complete one oscillation is known as the wave's time period.
Magnet is suspended like a free body in a vibration magnetometer.
$\mathrm{T}=2 \pi \sqrt{\dfrac{1}{\mathrm{~g}}}$
Twist causes a reduction in length and from the above expression we can say that if length is reduced then the time period will decrease. Therefore, if the twists in the suspension fibre are removed, the time period increases.
Hence,the correct answer is option B.
Additional information: A bar magnet held freely in a uniform magnetic field begins to move in a straightforward harmonic manner about the equilibrium position when it is moved from that location. The sign indicating that the torque works in the direction of decreasing $\tau=-M B_{H} \theta$ is $\tau=-m B_{H}(2 \ell \sin \theta)=-M B_{H} \sin \theta$ .If $\tau=-M B_{H} \theta$ is small , then$\tau=-M B_{H} \theta$
Note: It is a tool for measuring the horizontal component of the earth's magnetic field as well as comparing the magnetic moments of two bar magnets and the horizontal components of the earth's magnetic field at two locations.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

Young's Double Slit Experiment Step by Step Derivation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Displacement-Time Graph and Velocity-Time Graph for JEE

Uniform Acceleration

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Degree of Dissociation and Its Formula With Solved Example for JEE

Free Radical Substitution Mechanism of Alkanes for JEE Main 2025

If a wire of resistance R is stretched to double of class 12 physics JEE_Main
