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Three capacitors each of capacity 4μF are to be connected in such a way that the effective capacitance is 6μF . This can be done by:
A) Connecting them in series
B) Connecting them in parallel
C) Connecting two in series and one in parallel
D) Connecting two in parallel and one in series

Answer
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Hint: Use the formula of equivalent capacitance of both series and parallel connection to check whether they are connected in series or parallel or two in series, one in parallel or two in parallel, one in series. Equivalent capacitance, of which case is similar to the given effective capacitance, is the required answer.

Complete step by step solution:
Let, the three capacitors are C1 , C2 and C3 .
By the given problem, C1=C2=C3=4μF .
Case-1: let the given three capacitors are connected in series. Then, the total capacitance will be,
Ctot=11C1+1C2+1C3 where C1 , C2 , C3 are the three given capacitors.
Therefore, using the values of the three capacitors, we get,
Ctot=114+14+14μF
1(1+1+1)4μF
43μF
Case-2: let the given three capacitors are connected in parallel. Then, the total capacitance will be,
Ctot=C1+C2+C3
Now, using the values of the given three capacitors, we get,
Ctot=(4+4+4)μF
12μF
Case-3: let the given three capacitors are connected as two in series and one in parallel. Then, the total capacitance of the first two capacitors connected in series will be,
C=11C1+1C2
Therefore, C=1(1+1)4μF
42μF
2μF
Now, if the third capacitor is connected in parallel with the first two, the total effective capacitance will be,
Ctot=C+C3
Now, as C=2μF and C3=4μF we get,
Ctot=(2+4)μF
6μF
Therefore, the total capacitance in this case is 6μF.
Case-4: let the given three capacitors are connected as two in parallel and one in series. Then, the total capacitance of the first two capacitors connected in parallel will be,
C=C1+C2
Therefore, C=(4+4)μF
8μF
Now, if the third capacitor is connected in series with the first two, the total effective capacitance will be,
Ctot=11C+1C3μF
118+14μF
83μF
As it is given, that the effective capacitance is 6μF,

So, the correct answer is (C), Connecting two in series and one in parallel.

Note: In series connection, capacitances diminish, while capacitances add-in parallel connection. The total capacitance in case of series connection is less than the capacitance of any one individual capacitor’s capacitance.