
There are \[15\] terms in an arithmetic progression. Its first term is \[5\] and its sum is\[390\]. The middle term is
a) 23
b) 26
c) 29
d) 32
Answer
216.3k+ views
Hint:Using the general formula of the sum of n terms of AP which is given as\[{S_n} = \dfrac{n}{2}[2a + (n - 1)d]\] and by substituting the given values, we will solve for common difference d and then we will find the value of the middle term i.e. the eighth term using the formula\[{t_n} = a + (n - 1)d\]. Remember the value of n will be different in both formulas.
Formula Used:
\[{S_n} = \dfrac{n}{2}[2a + (n - 1)d]\]
\[{t_n} = a + (n - 1)d\].
Complete step by step Solution:
Given values: Number of terms (n) =\[15\]
First-term of arithmetic progression (a) =\[5\]
Sum of 15 terms \[{S_{15}} = 390\]
Use the formula of sum of n terms in Arithmetic Progression i.e.
\[{S_n} = \dfrac{n}{2}[2a + (n - 1)d]\]
Here\[{S_n} = 390\] ,\[n = 15\],\[a = 5\]
Substitute the given values in the above formula and get the value of common difference d
\[390 = \dfrac{{15}}{2}[2 \times 5 + (15 - 1)d]\]
Simplify it by opening the brackets
\[390 = \dfrac{{15}}{2}[10 + 14d]\]
\[390 \times 2 = 15\,[10 + 14d]\]
\[780 = 15\,[10 + 14d]\]
\[\dfrac{{780}}{{15}} = \,[10 + 14d]\]
\[52=10+14d\]
Solve for d
\[52 - 10 = 14d\]
\[42 = 14d\]
Therefore, \[d = \dfrac{{42}}{{14}} = 3\]
And now we will find the value of the middle term. In this question, the number of terms i.e. \[n = 15\] is an odd number. The formula to find the middle term in case n is an odd number is given by \[\dfrac{n+1}{2}\] . Put \[n = 15\] to get the middle term
\[\dfrac{{15 + 1}}{2} = \dfrac{{16}}{2} = {8^{th}}\]
The middle of the given sequence is \[{8^{th}}\] term. To find the value of \[{8^{th}}\] term of the given series, substitute given values in the formula\[{t_n} = a + (n - 1)d\]. Remember the value of n will be 8 in this formula.
Put \[a=5\]],\[n = 8\] and \[d = 3\] in the formula \[{t_n} = a + (n - 1)d\]
\[{t_8} = 5 + (8 - 1) \times 3\]
\[{t_8} = 5 + 21\]
Therefore, \[t_s=26\]
The middle term is\[26\].
Hence, the correct option is b.
Note: While solving for the middle term of AP using the formula\[{t_n} = a + (n - 1)d\], the value of n should be taken as 8 since the eighth term is the middle term of the given arithmetic progression.
Formula Used:
\[{S_n} = \dfrac{n}{2}[2a + (n - 1)d]\]
\[{t_n} = a + (n - 1)d\].
Complete step by step Solution:
Given values: Number of terms (n) =\[15\]
First-term of arithmetic progression (a) =\[5\]
Sum of 15 terms \[{S_{15}} = 390\]
Use the formula of sum of n terms in Arithmetic Progression i.e.
\[{S_n} = \dfrac{n}{2}[2a + (n - 1)d]\]
Here\[{S_n} = 390\] ,\[n = 15\],\[a = 5\]
Substitute the given values in the above formula and get the value of common difference d
\[390 = \dfrac{{15}}{2}[2 \times 5 + (15 - 1)d]\]
Simplify it by opening the brackets
\[390 = \dfrac{{15}}{2}[10 + 14d]\]
\[390 \times 2 = 15\,[10 + 14d]\]
\[780 = 15\,[10 + 14d]\]
\[\dfrac{{780}}{{15}} = \,[10 + 14d]\]
\[52=10+14d\]
Solve for d
\[52 - 10 = 14d\]
\[42 = 14d\]
Therefore, \[d = \dfrac{{42}}{{14}} = 3\]
And now we will find the value of the middle term. In this question, the number of terms i.e. \[n = 15\] is an odd number. The formula to find the middle term in case n is an odd number is given by \[\dfrac{n+1}{2}\] . Put \[n = 15\] to get the middle term
\[\dfrac{{15 + 1}}{2} = \dfrac{{16}}{2} = {8^{th}}\]
The middle of the given sequence is \[{8^{th}}\] term. To find the value of \[{8^{th}}\] term of the given series, substitute given values in the formula\[{t_n} = a + (n - 1)d\]. Remember the value of n will be 8 in this formula.
Put \[a=5\]],\[n = 8\] and \[d = 3\] in the formula \[{t_n} = a + (n - 1)d\]
\[{t_8} = 5 + (8 - 1) \times 3\]
\[{t_8} = 5 + 21\]
Therefore, \[t_s=26\]
The middle term is\[26\].
Hence, the correct option is b.
Note: While solving for the middle term of AP using the formula\[{t_n} = a + (n - 1)d\], the value of n should be taken as 8 since the eighth term is the middle term of the given arithmetic progression.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
Understanding Electromagnetic Waves and Their Importance

Geostationary and Geosynchronous Satellites Explained

Inertial and Non-Inertial Frame of Reference Explained

Clemmensen and Wolff Kishner Reductions Explained for JEE & NEET

JEE Main 2023 January 29th Shift 2 Physics Question Paper with Answer Keys and Solutions

Current Loop as a Magnetic Dipole: Concept, Derivation, and Examples

Other Pages
NCERT Solutions for Class 11 Maths Chapter Chapter 4 Complex Numbers And Quadratic Equations

JEE Main Correction Window 2026 Session 1 Dates Announced - Edit Form Details, Dates and Link

Alpha, Beta, and Gamma Decay Explained for JEE & NEET

Devuthani Ekadashi 2025: Correct Date, Shubh Muhurat, Parana Time & Puja Vidhi

Quadratic Equation Questions with Solutions & PDF Practice Sets

Photosynthesis explained for students

