
The values of ${X_L}$, ${X_C}$ and $R$ in an AC circuit are $8\,\Omega $, $6\,\Omega $ and $10\,\Omega $ respectively. The total impedance of the circuit:
(A) $10.2\,\Omega $
(B) $12.2\,\Omega $
(C) $10\,\Omega $
(D) $24.4\,\Omega $
Answer
232.8k+ views
Hint: The impedance of the circuit is determined by using the impedance of the circuit formula, by using this formula and also by using the values of the inductive reactance, capacitive reactance and the resistance values, then the impedance in the circuit can be determined.
Formula used:
The impedance of the circuit is given by,
$Z = \sqrt {{R^2} + {{\left( {{X_L} - {X_C}} \right)}^2}} $
Where, $Z$ is the impedance of the circuit, ${X_L}$ is the inductive reactance of the circuit, ${X_C}$ is the capacitive reactance of the circuit and $R$ is the resistance of the circuit.
Complete step by step solution:
Given that,
The inductive reactance of the circuit is, ${X_L} = 8\,\Omega $
The capacitive reactance of the circuit is, ${X_C} = 6\,\Omega $
The resistance of the circuit is, $R = 10\,\Omega $
Now,
The impedance of the circuit is given by,
$Z = \sqrt {{R^2} + {{\left( {{X_L} - {X_C}} \right)}^2}} \,................\left( 1 \right)$
By substituting the inductive reactance of the circuit, the capacitive reactance of the circuit and the resistance of the circuit in the above equation (1), then the above equation (1) is written as,
$Z = \sqrt {{{10}^2} + {{\left( {8 - 6} \right)}^2}} $
By subtracting the terms in the above equation, then the above equation is written as,
$Z = \sqrt {{{10}^2} + {2^2}} $
By squaring the terms inside the square root in the above equation, then the above equation is written as,
$Z = \sqrt {100 + 4} $
By adding the terms inside the square root in the above equation, then the above equation is written as,
$Z = \sqrt {104} $
By taking the square root in the above equation, then the above equation is written as,
$Z = 10.19\,\Omega $
Then the above equation is approximately written as,
$Z \simeq 10.2\,\Omega $
Hence, the option (A) is the correct answer.
Note: The impedance of the circuit is dependent only on the resistance of the circuit, the inductive reactance of the circuit, the capacitive reactance of the circuit. The impedance is also the form of the resistance and it is the measure of the overall opposition of the current in the circuit.
Formula used:
The impedance of the circuit is given by,
$Z = \sqrt {{R^2} + {{\left( {{X_L} - {X_C}} \right)}^2}} $
Where, $Z$ is the impedance of the circuit, ${X_L}$ is the inductive reactance of the circuit, ${X_C}$ is the capacitive reactance of the circuit and $R$ is the resistance of the circuit.
Complete step by step solution:
Given that,
The inductive reactance of the circuit is, ${X_L} = 8\,\Omega $
The capacitive reactance of the circuit is, ${X_C} = 6\,\Omega $
The resistance of the circuit is, $R = 10\,\Omega $
Now,
The impedance of the circuit is given by,
$Z = \sqrt {{R^2} + {{\left( {{X_L} - {X_C}} \right)}^2}} \,................\left( 1 \right)$
By substituting the inductive reactance of the circuit, the capacitive reactance of the circuit and the resistance of the circuit in the above equation (1), then the above equation (1) is written as,
$Z = \sqrt {{{10}^2} + {{\left( {8 - 6} \right)}^2}} $
By subtracting the terms in the above equation, then the above equation is written as,
$Z = \sqrt {{{10}^2} + {2^2}} $
By squaring the terms inside the square root in the above equation, then the above equation is written as,
$Z = \sqrt {100 + 4} $
By adding the terms inside the square root in the above equation, then the above equation is written as,
$Z = \sqrt {104} $
By taking the square root in the above equation, then the above equation is written as,
$Z = 10.19\,\Omega $
Then the above equation is approximately written as,
$Z \simeq 10.2\,\Omega $
Hence, the option (A) is the correct answer.
Note: The impedance of the circuit is dependent only on the resistance of the circuit, the inductive reactance of the circuit, the capacitive reactance of the circuit. The impedance is also the form of the resistance and it is the measure of the overall opposition of the current in the circuit.
Recently Updated Pages
Circuit Switching vs Packet Switching: Key Differences Explained

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Electricity and Magnetism Explained: Key Concepts & Applications

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

Understanding Uniform Acceleration in Physics

Understanding the Electric Field of a Uniformly Charged Ring

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Derivation of Equation of Trajectory Explained for Students

