
The unit of magnification is
A. $m $
B. ${m^2} $
C. ${m^{ - 1}} $
D. None of these
Answer
232.8k+ views
Hint In the below solution, we will proceed to the overview of the term magnification, the definition and the expression of the magnification. We take the ratio between the image distance and the object distance.
Complete step by step answer
The magnification has no units because that is the ratio of the measurement. It is the ratio of the size of an image to the size of an object. Hence, it is a dimensionless constant. We also say it as the ratio of the distances, magnification is the image distance to the object distance.
The magnification can be expressed as,
$M = \dfrac{{{D_i}}}{{{D_o}}} $
$M = \dfrac{{{H_i}}}{{{H_o}}} $
Where,
$M $is the magnification
$D $is the distance from the image
$D $is the distance from the object
${H_i} $is the height of the image.
${H_o} $is the height of the object.
Magnification glass or the microscope is used for the magnification. The glass is being very focused on objects and the magnification produces an image. If the magnification becomes negative, and the magnification of the image is inverted.
When the two media is different from the two sides on the lens, the magnification is expressed as the,
$M = \dfrac{{n{D_o}}}{{n'{D_o}}} $
Where,
$n $is the refractive index
Since, the magnification is the ratio of the two lengths, and therefore it has no units.
Hence, from the above multiple answers, option D is correct.
Note Units are the standards of the measurement of the physical quantities. These physical quantities are divided into two types. They are fundamental and derived units. We use the fundamental physical quantities like length, mass and time. These are the three systems of the units.
Complete step by step answer
The magnification has no units because that is the ratio of the measurement. It is the ratio of the size of an image to the size of an object. Hence, it is a dimensionless constant. We also say it as the ratio of the distances, magnification is the image distance to the object distance.
The magnification can be expressed as,
$M = \dfrac{{{D_i}}}{{{D_o}}} $
$M = \dfrac{{{H_i}}}{{{H_o}}} $
Where,
$M $is the magnification
$D $is the distance from the image
$D $is the distance from the object
${H_i} $is the height of the image.
${H_o} $is the height of the object.
Magnification glass or the microscope is used for the magnification. The glass is being very focused on objects and the magnification produces an image. If the magnification becomes negative, and the magnification of the image is inverted.
When the two media is different from the two sides on the lens, the magnification is expressed as the,
$M = \dfrac{{n{D_o}}}{{n'{D_o}}} $
Where,
$n $is the refractive index
Since, the magnification is the ratio of the two lengths, and therefore it has no units.
Hence, from the above multiple answers, option D is correct.
Note Units are the standards of the measurement of the physical quantities. These physical quantities are divided into two types. They are fundamental and derived units. We use the fundamental physical quantities like length, mass and time. These are the three systems of the units.
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