
The total number of contributing structures showing hyperconjugation (involving $C - H$ bonds) for the following carbocation is:

(A) 4
(B) 5
(C) 6
(D) 7
Answer
235.8k+ views
Hint: For this problem, we have to count the total number of alpha hydrogens that are attached to the alpha carbons because the number of hyperconjugation structures is directly proportional to the number of alpha hydrogen present in the structure.
Complete step by step solution:
- In the given question, we have to explain the total number of contributing structures which will show hyperconjugation.
- Now, firstly we should know about the hyperconjugation as it is a process in which the delocalisation of the electron will take place.
- The delocalisation of the electron takes place between the sigma or single bond and pi bond or non-bonding lone pair.
- So, to calculate the total number of conjugating structures, the compound must have the alpha hydrogen.
- Now, alpha hydrogen is the hydrogen which is directly attached to the alpha carbon and alpha carbon is the carbon which is directly attached to the functional group or carbocation.
- Also, we know that the total number of hyperconjugation structures is directly proportional to the total number of alpha hydrogen atoms present in the structure.
- So, in the given compound as we can see that there is three alpha carbon that is attached to the carbocation directly.
- And out of the left alpha carbon has three alpha hydrogen, right alpha carbon has two alpha hydrogen and the alpha carbon that is present below the carbocation has one alpha carbocation.
- So, the total number of alpha-hydrogen will be $3 + 2 + 1 = 5$.
Therefore, option (B) is the correct answer.
Note: Hyperconjugation is different from that of the resonance because in hyperconjugation the delocalisation of the sigma and non-bonding electron takes place whereas in resonance the delocalisation of the pi electrons takes place only.
Complete step by step solution:
- In the given question, we have to explain the total number of contributing structures which will show hyperconjugation.
- Now, firstly we should know about the hyperconjugation as it is a process in which the delocalisation of the electron will take place.
- The delocalisation of the electron takes place between the sigma or single bond and pi bond or non-bonding lone pair.
- So, to calculate the total number of conjugating structures, the compound must have the alpha hydrogen.
- Now, alpha hydrogen is the hydrogen which is directly attached to the alpha carbon and alpha carbon is the carbon which is directly attached to the functional group or carbocation.
- Also, we know that the total number of hyperconjugation structures is directly proportional to the total number of alpha hydrogen atoms present in the structure.
- So, in the given compound as we can see that there is three alpha carbon that is attached to the carbocation directly.
- And out of the left alpha carbon has three alpha hydrogen, right alpha carbon has two alpha hydrogen and the alpha carbon that is present below the carbocation has one alpha carbocation.
- So, the total number of alpha-hydrogen will be $3 + 2 + 1 = 5$.
Therefore, option (B) is the correct answer.
Note: Hyperconjugation is different from that of the resonance because in hyperconjugation the delocalisation of the sigma and non-bonding electron takes place whereas in resonance the delocalisation of the pi electrons takes place only.
Recently Updated Pages
JEE Main Result 2026 Session 1 OUT Download Scorecard Percentile – Check at jeemain.nta.nic.in

Top 10 NIT Colleges in India 2026 Rank Wise Fees Cutoff Placement

NIT Cutoff 2026 Tier 1 2 3 4 Category Wise Opening Closing Ranks

JEE Main 2026 Final Answer Key OUT Check Session 1 PDF and Result Updates

JEE Main 2026 Expected Cutoff – Category Wise Marks & Qualifying Percentile

JEE Main College Predictor 2026 – Predict Colleges by Rank & Percentile

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Electromagnetic Waves and Their Importance

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 4 The D And F Block Elements - 2025-26

Biomolecules Class 12 Chemistry Chapter 10 CBSE Notes - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules - 2025-26

