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# The power dissipated in a transmission wire carrying current I and voltage V is inversely proportional to :(A) V(B) ${V^2}$ (C) $\sqrt V$(D) $\sqrt I$ (E) I

Last updated date: 12th Aug 2024
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Hint Power transmitting through an electrical wire is given by $P = VI$ , power responsible for heat effect or power loss is given by ${P_H} = {I^2}R$ . Substitute this in the earlier equation. From this we know that power is inversely proportional to the square of the voltage.

Complete step-by-step solution
As we know that the power transmitted through an electrical wire is given as:
$P = VI$ --1
And in this wire, the current is sole responsible for the production of heat,
${P_H} = {I^2}R$ --2
Substituting 1 in 2 we get,
${P_H} = {(\dfrac{P}{V})^2}R$ ,
Therefore, when the voltage decreases by a factor, power will increase by the square of that factor,
Here we can we that, power lost in transmission is inversely proportional to ${V^2}$

Therefore, the correct answer is option B

Note Power lost solely depends on the electric current passing through it, that’s the same reason why wire coming to our home from a nearby station is ramped up to such a high voltage. It is done to minimize current and maximize voltage to reduce the energy lost as heat between 2 points