The physical quantity having the dimensions \[[{M^{ - 1}}{L^{ - 3}}{T^3}{A^2}]\]
A. Resistance
B. Resistivity
C. Electrical Conductivity
D. Electromotive force
Answer
249.6k+ views
Hint: In order to solve this question, we should know that every physical quantity has a dimensional formula that is determined by its mathematical expression, and here we will first determine the Dimensional formula of the given option and then matches it with the given dimensions.
Complete step by step solution:
Let us start with the dimensions of Electromotive force which is defined as the work done per unit charge so, its dimension is $[M{L^2}{T^{ - 3}}{A^{ - 1}}]$. and Dimensions of Resistance which is defined as the electromotive force per unit current so, its dimensions is $[M{L^2}{T^{ - 3}}{A^{ - 2}}]$.
Now As we know, the resistivity of a material is calculated as,
$\rho = \dfrac{m}{{n{e^2}t}}$
where, m is the mass having dimensions of $[M]$ ,n is the number of electrons per unit volume having dimensions of $[{L^{ - 3}}]$, e is the electronic charge having dimensions of $[AT]$ and t denotes for time having dimensions of $[T]$.
Now, putting all dimension into resistivity formula we get dimensions of Resistivity as,
$\rho = \dfrac{{[M]}}{{[{L^{ - 3}}{A^2}{T^3}]}} \\
\Rightarrow \rho = [M{L^3}{A^{ - 2}}{T^{ - 3}}] \\ $
Now, since we know that electrical conductivity is related to resistivity as,
$\sigma = \dfrac{1}{\rho }$
Hence, the dimensional formula for electrical conductivity will be the inverse of the dimensional formula for resistivity hence, we get;
$\sigma = \dfrac{1}{{[M{L^3}{A^{ - 2}}{T^{ - 3}}}}] \\
\Rightarrow \sigma = [{M^{ - 1}}{L^{ - 3}}{A^2}{T^3}] \\ $
And given dimensional formula is \[[{M^{ - 1}}{L^{ - 3}}{T^3}{A^2}]\] and it matches with the dimensional formula of electrical conductivity. The dimensional formula of resistance is $[M{L^2}{A^{ - 2}}{T^{ - 3}}]$ and the dimensional formula of electromotive force is $[M{L^2}{A^{ - 1}}{T^{ - 3}}]$, so only the option of electrical conductivity matches the given dimensional formula.
Hence, the correct option is C.
Note: It should be remembered that, $[A]$ denotes the dimensional formula of electric current and there are mainly seven fundamental physical quantities that can be used to determine any other physical quantity dimensions and these seven fundamental physical quantities are Mass, Length, Time, Current, Amount of Substance, Luminous Intensity, and Temperature.
Complete step by step solution:
Let us start with the dimensions of Electromotive force which is defined as the work done per unit charge so, its dimension is $[M{L^2}{T^{ - 3}}{A^{ - 1}}]$. and Dimensions of Resistance which is defined as the electromotive force per unit current so, its dimensions is $[M{L^2}{T^{ - 3}}{A^{ - 2}}]$.
Now As we know, the resistivity of a material is calculated as,
$\rho = \dfrac{m}{{n{e^2}t}}$
where, m is the mass having dimensions of $[M]$ ,n is the number of electrons per unit volume having dimensions of $[{L^{ - 3}}]$, e is the electronic charge having dimensions of $[AT]$ and t denotes for time having dimensions of $[T]$.
Now, putting all dimension into resistivity formula we get dimensions of Resistivity as,
$\rho = \dfrac{{[M]}}{{[{L^{ - 3}}{A^2}{T^3}]}} \\
\Rightarrow \rho = [M{L^3}{A^{ - 2}}{T^{ - 3}}] \\ $
Now, since we know that electrical conductivity is related to resistivity as,
$\sigma = \dfrac{1}{\rho }$
Hence, the dimensional formula for electrical conductivity will be the inverse of the dimensional formula for resistivity hence, we get;
$\sigma = \dfrac{1}{{[M{L^3}{A^{ - 2}}{T^{ - 3}}}}] \\
\Rightarrow \sigma = [{M^{ - 1}}{L^{ - 3}}{A^2}{T^3}] \\ $
And given dimensional formula is \[[{M^{ - 1}}{L^{ - 3}}{T^3}{A^2}]\] and it matches with the dimensional formula of electrical conductivity. The dimensional formula of resistance is $[M{L^2}{A^{ - 2}}{T^{ - 3}}]$ and the dimensional formula of electromotive force is $[M{L^2}{A^{ - 1}}{T^{ - 3}}]$, so only the option of electrical conductivity matches the given dimensional formula.
Hence, the correct option is C.
Note: It should be remembered that, $[A]$ denotes the dimensional formula of electric current and there are mainly seven fundamental physical quantities that can be used to determine any other physical quantity dimensions and these seven fundamental physical quantities are Mass, Length, Time, Current, Amount of Substance, Luminous Intensity, and Temperature.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Instantaneous Velocity Explained: Formula, Examples & Graphs

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Hybridisation in Chemistry – Concept, Types & Applications

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2025-26

CBSE Notes Class 11 Physics Chapter 4 - Laws of Motion - 2025-26

