
The oxidation number of C in HNC is:
(A) +2
(B) -3
(C) +3
(D) 0
Answer
233.1k+ views
Hint: We must keep in mind the basics of oxidation and reduction. Oxidation means a loss of hydrogen atom while reduction means a gain of hydrogen atom. Also, we can formulate oxidation as the gain of an electron and reduction as the loss of an electron. Accordingly, we can easily solve the given question.
Complete step-by step answer:
We know that the oxidation number of Hydrogen atom (H) is $+1 .$ As Nitrogen is more electronegative than Carbon, the oxidation number of Nitrogen is - 3. The Net charge on the compound is zero.
Now, we can find oxidation number of Carbon atom from the given equation:
Let the oxidation number of Carbon atom in the given compound be $\mathrm{x}$, $1+(-3)+x=0$
$\mathrm{x}=+2$
Hence, the correct option is $\mathrm{A}$
Note: We might get confused by the term reduction meaning a gain in hydrogen atom. But the correct way to remember this is that hydrogen atom has a positive charge and as reduction also means a loss of electron or a loss in negative charge, we can determine that a gain in hydrogen atom is equivalent to a loss in electron. Hence, we can easily remember the concept of reduction this way.
Complete step-by step answer:
We know that the oxidation number of Hydrogen atom (H) is $+1 .$ As Nitrogen is more electronegative than Carbon, the oxidation number of Nitrogen is - 3. The Net charge on the compound is zero.
Now, we can find oxidation number of Carbon atom from the given equation:
Let the oxidation number of Carbon atom in the given compound be $\mathrm{x}$, $1+(-3)+x=0$
$\mathrm{x}=+2$
Hence, the correct option is $\mathrm{A}$
Note: We might get confused by the term reduction meaning a gain in hydrogen atom. But the correct way to remember this is that hydrogen atom has a positive charge and as reduction also means a loss of electron or a loss in negative charge, we can determine that a gain in hydrogen atom is equivalent to a loss in electron. Hence, we can easily remember the concept of reduction this way.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

Organic Chemistry Some Basic Principles And Techniques Class 11 Chemistry Chapter 8 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reactions (2025-26)

