The orbital angular momentum of a p-electron is given as:
(a) \[\sqrt{3}\dfrac{h}{2\pi }\]
(b) \[\sqrt{\dfrac{3}{2}}\dfrac{h}{\pi }\]
(c) \[\sqrt{6}.\sqrt{\dfrac{h}{2\pi }}\]
(d) \[\dfrac{h}{\sqrt{2}\pi }\]
Answer
265.2k+ views
Hint: Bohr’s atomic model states many postulates for the arrangement of electrons in different orbits around the nucleus. According to one of his postulates, an electron can move around the nucleus in that circular orbital for which its angular momentum is an integral multiple of \[\dfrac{h}{2\pi }\].
Complete step by step answer:
According to the question, we need to find the angular momentum of a p-electron, i.e., this electron belongs to the p-orbital.
As we know, orbital angular momentum depends on ‘l’.
For p-orbital, the value of l = 1.
Formula of orbital angular momentum (m) is give as –
Orbital angular momentum = \[\sqrt{l(l+1)}\dfrac{h}{2\pi }\]
Since, l = 1.
Therefore,
Orbital angular momentum (m) = \[\sqrt{1(1+1)}\dfrac{h}{2\pi }\] = \[\sqrt{2}\dfrac{h}{2\pi }\]
On rationalization (i.e. multiplying numerator and denominator by\[\sqrt{2}\]), we get –
m =\[\dfrac{\sqrt{2}h}{2\pi }\times\dfrac{\sqrt{2}}{\sqrt{2}}\]
m =\[\dfrac{h}{\sqrt{2}\pi }\].
Therefore, the answer is – option (d) – The orbital angular momentum of a p-electron is given as \[\dfrac{h}{\sqrt{2}\pi }\].
Additional Information: The value of ‘l’ for different orbitals is as follows –
l = 0 for s-orbital
l = 1 for p-orbital
l = 2 for d-orbital
l = 3 for f-orbital
Note: The quantum number represents the complete address of an electron. There are four types of quantum numbers –
1. Principal quantum number (n)
- It tells about the size of the orbital, i.e. the average distance of an electron from the nucleus.
2. Azimuthal quantum number (l)
- It denotes the sub-level (orbital) to which the electron belongs.
- It ranges from 0 to (n-1).
3. Magnetic quantum number (m)
- It determines the preferred orientation of orbitals in space
- For each value of l, there are 2l+1 values of m.
4. Spin quantum number (s)
It tells about the direction of spin.
+1/2 represents clockwise spin.
-1/2 represents anti-clockwise spin.
Complete step by step answer:
According to the question, we need to find the angular momentum of a p-electron, i.e., this electron belongs to the p-orbital.
As we know, orbital angular momentum depends on ‘l’.
For p-orbital, the value of l = 1.
Formula of orbital angular momentum (m) is give as –
Orbital angular momentum = \[\sqrt{l(l+1)}\dfrac{h}{2\pi }\]
Since, l = 1.
Therefore,
Orbital angular momentum (m) = \[\sqrt{1(1+1)}\dfrac{h}{2\pi }\] = \[\sqrt{2}\dfrac{h}{2\pi }\]
On rationalization (i.e. multiplying numerator and denominator by\[\sqrt{2}\]), we get –
m =\[\dfrac{\sqrt{2}h}{2\pi }\times\dfrac{\sqrt{2}}{\sqrt{2}}\]
m =\[\dfrac{h}{\sqrt{2}\pi }\].
Therefore, the answer is – option (d) – The orbital angular momentum of a p-electron is given as \[\dfrac{h}{\sqrt{2}\pi }\].
Additional Information: The value of ‘l’ for different orbitals is as follows –
l = 0 for s-orbital
l = 1 for p-orbital
l = 2 for d-orbital
l = 3 for f-orbital
Note: The quantum number represents the complete address of an electron. There are four types of quantum numbers –
1. Principal quantum number (n)
- It tells about the size of the orbital, i.e. the average distance of an electron from the nucleus.
2. Azimuthal quantum number (l)
- It denotes the sub-level (orbital) to which the electron belongs.
- It ranges from 0 to (n-1).
3. Magnetic quantum number (m)
- It determines the preferred orientation of orbitals in space
- For each value of l, there are 2l+1 values of m.
4. Spin quantum number (s)
It tells about the direction of spin.
+1/2 represents clockwise spin.
-1/2 represents anti-clockwise spin.
Recently Updated Pages
JEE Main Mock Test 2025-26: Principles Related To Practical

JEE Main 2025-26 Experimental Skills Mock Test – Free Practice

JEE Main 2025-26 Electronic Devices Mock Test: Free Practice Online

JEE Main 2025-26 Mock Tests: Free Practice Papers & Solutions

JEE Main 2025-26: Magnetic Effects of Current & Magnetism Mock Test

JEE Main Statistics and Probability Mock Test 2025-26

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced Marks vs Rank 2025 - Predict Your IIT Rank Based on Score

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

NCERT Solutions For Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts Of Chemistry - 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

