The orbital angular momentum of a p-electron is given as:
(a) \[\sqrt{3}\dfrac{h}{2\pi }\]
(b) \[\sqrt{\dfrac{3}{2}}\dfrac{h}{\pi }\]
(c) \[\sqrt{6}.\sqrt{\dfrac{h}{2\pi }}\]
(d) \[\dfrac{h}{\sqrt{2}\pi }\]
Answer
262.5k+ views
Hint: Bohr’s atomic model states many postulates for the arrangement of electrons in different orbits around the nucleus. According to one of his postulates, an electron can move around the nucleus in that circular orbital for which its angular momentum is an integral multiple of \[\dfrac{h}{2\pi }\].
Complete step by step answer:
According to the question, we need to find the angular momentum of a p-electron, i.e., this electron belongs to the p-orbital.
As we know, orbital angular momentum depends on ‘l’.
For p-orbital, the value of l = 1.
Formula of orbital angular momentum (m) is give as –
Orbital angular momentum = \[\sqrt{l(l+1)}\dfrac{h}{2\pi }\]
Since, l = 1.
Therefore,
Orbital angular momentum (m) = \[\sqrt{1(1+1)}\dfrac{h}{2\pi }\] = \[\sqrt{2}\dfrac{h}{2\pi }\]
On rationalization (i.e. multiplying numerator and denominator by\[\sqrt{2}\]), we get –
m =\[\dfrac{\sqrt{2}h}{2\pi }\times\dfrac{\sqrt{2}}{\sqrt{2}}\]
m =\[\dfrac{h}{\sqrt{2}\pi }\].
Therefore, the answer is – option (d) – The orbital angular momentum of a p-electron is given as \[\dfrac{h}{\sqrt{2}\pi }\].
Additional Information: The value of ‘l’ for different orbitals is as follows –
l = 0 for s-orbital
l = 1 for p-orbital
l = 2 for d-orbital
l = 3 for f-orbital
Note: The quantum number represents the complete address of an electron. There are four types of quantum numbers –
1. Principal quantum number (n)
- It tells about the size of the orbital, i.e. the average distance of an electron from the nucleus.
2. Azimuthal quantum number (l)
- It denotes the sub-level (orbital) to which the electron belongs.
- It ranges from 0 to (n-1).
3. Magnetic quantum number (m)
- It determines the preferred orientation of orbitals in space
- For each value of l, there are 2l+1 values of m.
4. Spin quantum number (s)
It tells about the direction of spin.
+1/2 represents clockwise spin.
-1/2 represents anti-clockwise spin.
Complete step by step answer:
According to the question, we need to find the angular momentum of a p-electron, i.e., this electron belongs to the p-orbital.
As we know, orbital angular momentum depends on ‘l’.
For p-orbital, the value of l = 1.
Formula of orbital angular momentum (m) is give as –
Orbital angular momentum = \[\sqrt{l(l+1)}\dfrac{h}{2\pi }\]
Since, l = 1.
Therefore,
Orbital angular momentum (m) = \[\sqrt{1(1+1)}\dfrac{h}{2\pi }\] = \[\sqrt{2}\dfrac{h}{2\pi }\]
On rationalization (i.e. multiplying numerator and denominator by\[\sqrt{2}\]), we get –
m =\[\dfrac{\sqrt{2}h}{2\pi }\times\dfrac{\sqrt{2}}{\sqrt{2}}\]
m =\[\dfrac{h}{\sqrt{2}\pi }\].
Therefore, the answer is – option (d) – The orbital angular momentum of a p-electron is given as \[\dfrac{h}{\sqrt{2}\pi }\].
Additional Information: The value of ‘l’ for different orbitals is as follows –
l = 0 for s-orbital
l = 1 for p-orbital
l = 2 for d-orbital
l = 3 for f-orbital
Note: The quantum number represents the complete address of an electron. There are four types of quantum numbers –
1. Principal quantum number (n)
- It tells about the size of the orbital, i.e. the average distance of an electron from the nucleus.
2. Azimuthal quantum number (l)
- It denotes the sub-level (orbital) to which the electron belongs.
- It ranges from 0 to (n-1).
3. Magnetic quantum number (m)
- It determines the preferred orientation of orbitals in space
- For each value of l, there are 2l+1 values of m.
4. Spin quantum number (s)
It tells about the direction of spin.
+1/2 represents clockwise spin.
-1/2 represents anti-clockwise spin.
Recently Updated Pages
JEE Main 2026 Exam Date, Session 2 Results OUT, Cutoff Released, City Slip & Admit Card

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
Understanding Atomic Structure for Beginners

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding the Electric Field of a Charged Spherical Shell

Understanding Average and RMS Value in Electrical Circuits

Understanding Instantaneous Velocity

Other Pages
CBSE Notes Class 11 Chemistry Chapter 5 - Thermodynamics - 2025-26

JEE Advanced Marks vs Rank 2025 - Predict Your IIT Rank Based on Score

If osmotic pressure of a solution is 2atm at 273K then class 11 chemistry JEE_Main

CBSE Notes Class 11 Chemistry Chapter 6 - Equilibrium - 2025-26

Free Radical Substitution and Its Stepwise Mechanism

Which one of the following is not a nonideal solution class 11 chemistry JEE_Main

