
The number of precipitable halide ions in the sample \[\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{2}}Br \right]Cl\] will be:
A. 2
B. 3
C. 4
D. 1
Answer
163.5k+ views
Hint: Because the ions present in the coordination sphere do not dissociate and instead stay together in an aqueous solution, coordination compounds do not entirely break down into all of their ions. Only the substances that are joined to the complex produce ions.
Complete answer:We have been asked to find the number of precipitable ions in the given complex. Precipitation will occur only to the halogens which can be ionised from the given sample. Coordination complexes comprise of a central metal atom, a ligand, and some attacking groups which are ionizable when put in the aqueous solution. Salts can be divided into two categories, simple salt, and mixed salt, based on how many different types of ions they contain. Simple salts only include one kind of each cation and anion. For instance, KCl and NaCl. More than one type of cation or anion can be found in mixed salt. Additionally, there are two forms of mixed salts: coordination complex and double salt. Water entirely dissociates into its ion components after mixing with double salts. Water does not entirely separate coordination compounds into their cationic and anionic parts. If we look at the given complex, that is \[\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{2}}Br \right]Cl\], it’s dissociation in the solution can be seen as:
\[\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{2}}Br \right]Cl\to {{\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{2}}Br \right]}^{+}}+C{{l}^{-}}\], here we can see that we have one free chloride ion and that’s the only halogen ion that will participate in the reaction and lead to precipitation. Therefore, there is only 1 halide ion that is precipitable.
Hence, the correct option is D. 1
Note: When naming a coordination complex, the cation is written first, followed by the anion. The center metal atom is named with its oxidation number in roman numerals after the ligands are named in alphabetical order during the naming of the coordination sphere.
Complete answer:We have been asked to find the number of precipitable ions in the given complex. Precipitation will occur only to the halogens which can be ionised from the given sample. Coordination complexes comprise of a central metal atom, a ligand, and some attacking groups which are ionizable when put in the aqueous solution. Salts can be divided into two categories, simple salt, and mixed salt, based on how many different types of ions they contain. Simple salts only include one kind of each cation and anion. For instance, KCl and NaCl. More than one type of cation or anion can be found in mixed salt. Additionally, there are two forms of mixed salts: coordination complex and double salt. Water entirely dissociates into its ion components after mixing with double salts. Water does not entirely separate coordination compounds into their cationic and anionic parts. If we look at the given complex, that is \[\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{2}}Br \right]Cl\], it’s dissociation in the solution can be seen as:
\[\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{2}}Br \right]Cl\to {{\left[ Pt\left( N{{H}_{3}} \right)C{{l}_{2}}Br \right]}^{+}}+C{{l}^{-}}\], here we can see that we have one free chloride ion and that’s the only halogen ion that will participate in the reaction and lead to precipitation. Therefore, there is only 1 halide ion that is precipitable.
Hence, the correct option is D. 1
Note: When naming a coordination complex, the cation is written first, followed by the anion. The center metal atom is named with its oxidation number in roman numerals after the ligands are named in alphabetical order during the naming of the coordination sphere.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
