
The major aromatic product C in the following reaction sequence will be:

(1)

(2)

(3)

(4)

Answer
161.1k+ views
Hint: HBr is an example of an inorganic compound. HBr and its aqueous solution are useful as a reagent in the preparation of bromine compounds. HBr, when undergoing reaction with an alkene, forms a complex of alkyl bromide. HBr undergoes a reaction with alcohol to give an alkyl bromide as a product.
Complete Step by Step Solution:
The reaction of ketone with HBr in excess results in the breaking of the bond. The reaction is as follows:

Image: Reaction of ketone with HBr
As the HBr is in excess, so, the bromination at the o and p position takes place.
The next step is the reaction of A with alcoholic potassium hydroxide in presence of acid. The reaction of an alkyl halide in alcoholic potassium hydroxide results in the removal of halogen acid to form an alkene.
So, the reaction is,


Image: Reaction of A with alcoholic potassium hydroxide in presence of acid
The next step is the reaction of B with Ozone in the presence of acid.
Image: Reaction of B with Ozone in presence of acid
This is an ozonolysis reaction. Ozonolysis is a reaction in organic chemistry where the breaking of double or triple bonds of alkynes, alkenes or azo compounds takes place in reaction with ozone. Alkynes and alkenes form organic compounds where the replacement of multiple carbon-carbon bonds takes place by a carbonyl group whereas azo compounds give nitrosamines.
Hence, the product C is in option C.
Note: Students often get confused between the reaction of an alkyl halide with aqueous and alcoholic KOH. It is to be noted that the reaction of an alkyl halide with alcoholic KOH gives alkene as a product. But, when alkyl halide undergoes a reaction with aqueous KOH, it gives alcohol as a product.
Complete Step by Step Solution:
The reaction of ketone with HBr in excess results in the breaking of the bond. The reaction is as follows:

Image: Reaction of ketone with HBr
As the HBr is in excess, so, the bromination at the o and p position takes place.
The next step is the reaction of A with alcoholic potassium hydroxide in presence of acid. The reaction of an alkyl halide in alcoholic potassium hydroxide results in the removal of halogen acid to form an alkene.
So, the reaction is,


Image: Reaction of A with alcoholic potassium hydroxide in presence of acid
The next step is the reaction of B with Ozone in the presence of acid.
Image: Reaction of B with Ozone in presence of acid

This is an ozonolysis reaction. Ozonolysis is a reaction in organic chemistry where the breaking of double or triple bonds of alkynes, alkenes or azo compounds takes place in reaction with ozone. Alkynes and alkenes form organic compounds where the replacement of multiple carbon-carbon bonds takes place by a carbonyl group whereas azo compounds give nitrosamines.
Hence, the product C is in option C.
Note: Students often get confused between the reaction of an alkyl halide with aqueous and alcoholic KOH. It is to be noted that the reaction of an alkyl halide with alcoholic KOH gives alkene as a product. But, when alkyl halide undergoes a reaction with aqueous KOH, it gives alcohol as a product.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main Mock Test Series Class 12 Chemistry for FREE

Classification of Drugs Based on Pharmacological Effect, Drug Action

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Free Radical Substitution Mechanism of Alkanes for JEE Main 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

Solutions Class 12 Notes: CBSE Chemistry Chapter 1
