
The hybridization in \[{\rm{B}}{{\rm{F}}_{\rm{3}}}\] molecule is
A) \[sp\]
B) \[s{p^2}\]
C) \[s{p^3}\]
D) \[s{p^3}d\]
Answer
163.2k+ views
Hint: We know that hybridization is the process of mixing of orbitals of similar nature to give a new set of orbitals that have different shapes and energies. Here, we have to use a formula to know the hybridization of the molecule.
Formula Used:The formula of hybridization is,
\[H = \dfrac{{V + X - C + A}}{2}\]
Here, V is for valence electrons, X is the count of monovalent atoms that are bonded with the central atom, C is for cationic charge and A is for anionic charge.
Complete step by step solution:If the value of H is 4, that means, hybridization of the compound is \[s{p^3}\].
If the value of H is 3, that means, hybridization of the compound is \[s{p^2}\].
And if the value of H is 2,that means, the hybridization of the compound is \[sp\] .
Let’s check the hybridization of \[{\rm{B}}{{\rm{F}}_{\rm{3}}}\] molecule.
The valence electrons of B are 3 and the count of monovalent atoms in the compound is 3.
So,
\[H = \dfrac{{3 + 3}}{2} = 3\]
Therefore, the \[{\rm{B}}{{\rm{F}}_{\rm{3}}}\]molecule has the hybridization of \[s{p^2}\] .
Hence, option B is right.
Note:Another way to check hybridization of a compound is to check the count of groups surrounding the central atom. The surrounding groups are atoms that form bonds with the central atom and the lone pairs on the central atom. In \[{\rm{B}}{{\rm{F}}_{\rm{3}}}\], only three fluorine atoms form bonds with the boron atom and no lone pair is present on the Boron atom. So, the count of groups is three and therefore, the hybridization is \[s{p^2}\] .
Formula Used:The formula of hybridization is,
\[H = \dfrac{{V + X - C + A}}{2}\]
Here, V is for valence electrons, X is the count of monovalent atoms that are bonded with the central atom, C is for cationic charge and A is for anionic charge.
Complete step by step solution:If the value of H is 4, that means, hybridization of the compound is \[s{p^3}\].
If the value of H is 3, that means, hybridization of the compound is \[s{p^2}\].
And if the value of H is 2,that means, the hybridization of the compound is \[sp\] .
Let’s check the hybridization of \[{\rm{B}}{{\rm{F}}_{\rm{3}}}\] molecule.
The valence electrons of B are 3 and the count of monovalent atoms in the compound is 3.
So,
\[H = \dfrac{{3 + 3}}{2} = 3\]
Therefore, the \[{\rm{B}}{{\rm{F}}_{\rm{3}}}\]molecule has the hybridization of \[s{p^2}\] .
Hence, option B is right.
Note:Another way to check hybridization of a compound is to check the count of groups surrounding the central atom. The surrounding groups are atoms that form bonds with the central atom and the lone pairs on the central atom. In \[{\rm{B}}{{\rm{F}}_{\rm{3}}}\], only three fluorine atoms form bonds with the boron atom and no lone pair is present on the Boron atom. So, the count of groups is three and therefore, the hybridization is \[s{p^2}\] .
Recently Updated Pages
Fluid Pressure - Important Concepts and Tips for JEE

JEE Main 2023 (February 1st Shift 2) Physics Question Paper with Answer Key

Impulse Momentum Theorem Important Concepts and Tips for JEE

Graphical Methods of Vector Addition - Important Concepts for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 1) Physics Question Paper with Answer Key

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

NEET 2025 – Every New Update You Need to Know

Verb Forms Guide: V1, V2, V3, V4, V5 Explained
