
The following four solutions are kept in separate beakers and copper metal is put in each of them. Which solution will become blue after some time
(A) $AgN{O_3}$solution
(B) $Zn{(N{O_3})_2}$ solution
(C) $Ba{(N{O_3})_2}$ solution
(D) $NaN{O_3}$ solution
Answer
161.1k+ views
Hint: The feasibility of a reaction is described according to the chemical reactivity series. Solution will turn blue only which reacts with copper to form copper nitrate that is blue in colour.
Complete Step by Step Solution:
In the chemical reactivity series, the elements are arranged in the decreasing order of chemical reactivity. Thus, the element placed higher in the chemical reactivity series is more reactive and displaces the elements lower in the chemical reactivity series.
Thus, it is correct to say that copper will displace the metal from its solution which is placed below copper in the chemical reactivity series. $Zn,Ba,Na$are placed above copper hence, have greater reactivity so copper cannot displace them in their solution. But copper can displace silver from the $AgN{O_3}$ solution.
$Zn{(N{O_3})_2} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + Z{n^{ + 2}}$
$Ba{(N{O_3})_2} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + B{a^{ + 2}}$
\[NaN{O_3} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + N{a^ + }\]
The above written reactions are not feasible hence, adding copper metal to these solutions will not turn solution blue. Thus, the blue colour of the solution is because of the reaction
\[AgN{O_3} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + A{g^ + }\]
Hence, the correct answer is A.
Note: A feasible reaction is one which happens spontaneously in a practical time period without supply of extra energy. The spontaneity criteria for a reaction is given by Gibbs free energy which is negative for a spontaneous reaction. Kinetics play a crucial role in defining feasibility of a reaction. The conversion of graphite to diamond is a feasible reaction as it has a negative value of Gibbs free energy but it takes an infinite time hence the reaction is not possible.
Complete Step by Step Solution:
In the chemical reactivity series, the elements are arranged in the decreasing order of chemical reactivity. Thus, the element placed higher in the chemical reactivity series is more reactive and displaces the elements lower in the chemical reactivity series.
Thus, it is correct to say that copper will displace the metal from its solution which is placed below copper in the chemical reactivity series. $Zn,Ba,Na$are placed above copper hence, have greater reactivity so copper cannot displace them in their solution. But copper can displace silver from the $AgN{O_3}$ solution.
$Zn{(N{O_3})_2} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + Z{n^{ + 2}}$
$Ba{(N{O_3})_2} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + B{a^{ + 2}}$
\[NaN{O_3} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + N{a^ + }\]
The above written reactions are not feasible hence, adding copper metal to these solutions will not turn solution blue. Thus, the blue colour of the solution is because of the reaction
\[AgN{O_3} + C{u^{ + 2}} \to Cu{(N{O_3})_2} + A{g^ + }\]
Hence, the correct answer is A.
Note: A feasible reaction is one which happens spontaneously in a practical time period without supply of extra energy. The spontaneity criteria for a reaction is given by Gibbs free energy which is negative for a spontaneous reaction. Kinetics play a crucial role in defining feasibility of a reaction. The conversion of graphite to diamond is a feasible reaction as it has a negative value of Gibbs free energy but it takes an infinite time hence the reaction is not possible.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main Mock Test Series Class 12 Chemistry for FREE

Classification of Drugs Based on Pharmacological Effect, Drug Action

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Free Radical Substitution Mechanism of Alkanes for JEE Main 2025

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

Solutions Class 12 Notes: CBSE Chemistry Chapter 1
