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# The figure below shows regular hexagons, with charges at the vertices. In which of the following cases the electric field at the center is not zero.A) $4$ B) $3$C) $1$D) $2$

Last updated date: 22nd Jul 2024
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Hint: At the center of every hexagon, the electric field is zero. Here, the electric field will be zero because the charges of the same values with opposite charges will terminate each other i.e. ${\text{ + q}}$ and ${\text{ - q}}$ in each corner cancel out each other.

The charge at the position $1$ and the charge at the position $4$ cancel each other.
Whereas, the charges at positions $2$ , $5$ , and $3$ , $6$ will not cancel each other.

The magnitude of the electric field $\left( E \right)$occurred by a point charge with a charge of magnitude $Q$ , at some distance $r$ away from the point charge, is given by the equation $E = \dfrac{{k{\text{Q}}}}{{{r^2}}}$.
Where $k = 8.99 \times {10^9}{\text{ N }}\dfrac{{{{\text{m}}^2}}}{{{c^2}}}$.

Hence, the right answer is in option $(D) \Rightarrow 2$ .