
The end product of the reaction is \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}\xrightarrow{HN{{O}_{2}}}A\xrightarrow{PC{{l}_{5}}}B\xrightarrow{H.N{{H}_{2}}}C\]
(A) Ethyl cyanide
(B) Ethyl amine
(C) Methyl amine
(D) Acetamide
Answer
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Hint: In the first step catalyst plays a major role for conversion, in the second step dehydrating agent plays an important role and in the final step ammonolysis reaction takes place.
Complete Step by Step Solution:
In the first step, ethylamine is converted to ethyl alcohol which is product A. The method used for this conversion is At a temperature of 0 to 5 degrees Celsius, ethyl amine reacts with a Nitrous acid(obtained from \[NaN{{O}_{2}}\]solution and dilute \[HCl\]), to give ethyl diazonium chloride. This can be given a little heat in an aqueous medium to give ethanol.
\[{{C}_{2}}{{H}_{5}}N{{H}_{2}}+HONO\xrightarrow{NaN{{O}_{2}}/HCl}{{C}_{2}}{{H}_{5}}OH+{{H}_{2}}O+{{N}_{2}}\]
Product A is ethyl alcohol.
In the second step, ethyl alcohol is converted to ethyl chloride, in which a dehydrating agent is used. A dehydrating agent is a substance that dries or removes water from a material. In chemical reactions where dehydration occurs, the reacting molecule loses a molecule of water.
\[{{C}_{2}}{{H}_{5}}OH+PC{{l}_{5}}\xrightarrow{heat}{{C}_{2}}{{H}_{5}}Cl+HCl+POC{{l}_{3}}\]
Here, the dehydrating agent used is\[PC{{l}_{5}}\].
Product B is ethyl chloride.
In the last step, ethyl chloride is converted to ethyl amine here ammonolysis reaction will take place because of the presence of\[H.N{{H}_{2}}\]. When ammonia reacts with ethyl chloride, it undergoes an ammonolysis reaction to form ethyl amine. After the formation of ethyl amine (primary amine), it goes further to form secondary amine, tertiary amine, and quaternary ammonium
salt, respectively.
\[{{C}_{2}}{{H}_{5}}Cl+H.N{{H}_{2}}\to {{C}_{2}}{{H}_{5}}N{{H}_{2}}\]
The final product or product C is ethyl amine.
Hence, the correct option is option B that is ethyl amine.
Note: While conversion of reactions make sure that we use the catalyst properly and we should keep in mind the reactant and the final product, as well as we should make sure that the product formed in between is correct and accurate.
Complete Step by Step Solution:
In the first step, ethylamine is converted to ethyl alcohol which is product A. The method used for this conversion is At a temperature of 0 to 5 degrees Celsius, ethyl amine reacts with a Nitrous acid(obtained from \[NaN{{O}_{2}}\]solution and dilute \[HCl\]), to give ethyl diazonium chloride. This can be given a little heat in an aqueous medium to give ethanol.
\[{{C}_{2}}{{H}_{5}}N{{H}_{2}}+HONO\xrightarrow{NaN{{O}_{2}}/HCl}{{C}_{2}}{{H}_{5}}OH+{{H}_{2}}O+{{N}_{2}}\]
Product A is ethyl alcohol.
In the second step, ethyl alcohol is converted to ethyl chloride, in which a dehydrating agent is used. A dehydrating agent is a substance that dries or removes water from a material. In chemical reactions where dehydration occurs, the reacting molecule loses a molecule of water.
\[{{C}_{2}}{{H}_{5}}OH+PC{{l}_{5}}\xrightarrow{heat}{{C}_{2}}{{H}_{5}}Cl+HCl+POC{{l}_{3}}\]
Here, the dehydrating agent used is\[PC{{l}_{5}}\].
Product B is ethyl chloride.
In the last step, ethyl chloride is converted to ethyl amine here ammonolysis reaction will take place because of the presence of\[H.N{{H}_{2}}\]. When ammonia reacts with ethyl chloride, it undergoes an ammonolysis reaction to form ethyl amine. After the formation of ethyl amine (primary amine), it goes further to form secondary amine, tertiary amine, and quaternary ammonium
salt, respectively.
\[{{C}_{2}}{{H}_{5}}Cl+H.N{{H}_{2}}\to {{C}_{2}}{{H}_{5}}N{{H}_{2}}\]
The final product or product C is ethyl amine.
Hence, the correct option is option B that is ethyl amine.
Note: While conversion of reactions make sure that we use the catalyst properly and we should keep in mind the reactant and the final product, as well as we should make sure that the product formed in between is correct and accurate.
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