Answer
Verified
91.5k+ views
Hint: To solve this question, first identify the electronic configuration of both the given elements. Then understand which ions of the given elements are required. After that, remove the corresponding number of electrons from the elements and write their final electronic configurations.
Complete Step-by-Step answer:
The atomic numbers of the given elements, Europium and Cerium are 63 and 58 respectively. From this, the electronic configuration of Europium and Cerium can be written as follows:
Electronic configuration of europium = Eu = \[[Xe]4{f^7}6{s^2}\]
Electronic configuration of cerium = Ce = \[[Xe]4{f^1}5{d^1}6{s^2}\]
Now the conditions that have been given to us are that the europium atom is made bivalent and the cerium atom is made trivalent. Making an atom trivalent means removing three electrons from the atom.
Hence, after removing 2 electrons from europium and 3 electrons from cerium, the electron configurations thus obtained are:
For Europium: \[[Xe]4{f^7}\]
For cerium: \[[Xe]4{f^1}\]
Hence, Option D is the correct option.
Note: While all lanthanides form relatively large trivalent (3+) ions, Eu and cerium (Ce) have additional valances, europium forms 2+ ions, and Ce forms 4+ ions, leading to chemical reaction differences in how these ions can partition versus the 3+ REEs.
Complete Step-by-Step answer:
The atomic numbers of the given elements, Europium and Cerium are 63 and 58 respectively. From this, the electronic configuration of Europium and Cerium can be written as follows:
Electronic configuration of europium = Eu = \[[Xe]4{f^7}6{s^2}\]
Electronic configuration of cerium = Ce = \[[Xe]4{f^1}5{d^1}6{s^2}\]
Now the conditions that have been given to us are that the europium atom is made bivalent and the cerium atom is made trivalent. Making an atom trivalent means removing three electrons from the atom.
Hence, after removing 2 electrons from europium and 3 electrons from cerium, the electron configurations thus obtained are:
For Europium: \[[Xe]4{f^7}\]
For cerium: \[[Xe]4{f^1}\]
Hence, Option D is the correct option.
Note: While all lanthanides form relatively large trivalent (3+) ions, Eu and cerium (Ce) have additional valances, europium forms 2+ ions, and Ce forms 4+ ions, leading to chemical reaction differences in how these ions can partition versus the 3+ REEs.
Recently Updated Pages
Name the scale on which the destructive energy of an class 11 physics JEE_Main
Write an article on the need and importance of sports class 10 english JEE_Main
Choose the exact meaning of the given idiomphrase The class 9 english JEE_Main
Choose the one which best expresses the meaning of class 9 english JEE_Main
What does a hydrometer consist of A A cylindrical stem class 9 physics JEE_Main
A motorcyclist of mass m is to negotiate a curve of class 9 physics JEE_Main
Other Pages
Velocity of car at t 0 is u moves with a constant acceleration class 11 physics JEE_Main
Derive an expression for maximum speed of a car on class 11 physics JEE_Main
A soldier with a machine gun falling from an airplane class 11 physics JEE_MAIN
If a wire of resistance R is stretched to double of class 12 physics JEE_Main
The vapour pressure of pure A is 10 torr and at the class 12 chemistry JEE_Main
Electric field due to uniformly charged sphere class 12 physics JEE_Main