Question

The effect of increasing the pressure on the equilibrium [ 2A+3B\rlhar3A+2B ] is
A. Forward reaction is favoured
B. Backward reaction is favoured
C. No effect
D. None of the above

Answer 1

Hint: The rate of reaction is affected by increasing or decreasing pressure and temperature. If the reactant moles are more in the reaction then on increasing pressure the rate of forward reaction will increase and backward reaction will decrease and on decreasing pressure the rate of backward reaction will increase and forward reaction will increase.

Complete answer:A chemical reaction in which the formation of product and as well as the formation of reactant takes place such type of reaction is called a reversible reaction. And reversible reactions try to attain chemical equilibrium. Equilibrium is a state where the rate of formation of product is equal to the rate of formation of reactant. According to Le chatelier’s principle on increasing the pressure, the reaction will shift towards the direction where fewer molecules are present and on decreasing pressure, the reaction will shift towards the direction where more molecules are present.

In the given reaction [ 2A+3B\rlhar3A+2B ] as we can see that-
Total moles of reactant are 2A + 3B = 5
And, Total moles of products are 3A + 2B = 5
Thus, the total moles of the reactant and the products are equal so there will be no effect of pressure on the reaction.

Thus, Option (C) is correct

Note: Temperature also affects the reversible reaction. In an endothermic reversible reaction, the temperature increases the rate of forward reaction (i.e, in favour of the reactant). In an exothermic reversible reaction, the temperature increases the rate of backward reaction(i.e, in favour of products).