
The deeper we go inside a flowing river, the fluid friction:
A) decreases
B) increases
C) remains same
D) becomes zero
Answer
244.5k+ views
Hint: In this question use the concept as you go deeper into a flowing river, you spend more energy as you try to move forward. The speed of swimming decreases. So, the friction increases the deeper we go in a flowing river.
Complete step by step solution:
As we know that the friction is the type of force which resists the motion of any two solid surfaces or fluid layers. When this friction is experienced inside any fluid then it is called fluid friction or fluid viscosity.
Fluid friction is described as the friction between any two viscous layers of a fluid that are moving with respect to each other. The fluid friction depends upon the viscosity of the fluid and the velocity gradient. The velocity gradient is the rate of change of velocity or simply the ratio of velocity and distance between layers.
As we go deeper inside a flowing river, we require more force to keep the layers flowing with flow.
$ \Rightarrow F = \eta \dfrac{{VA}}{L}$
Where F is the force required to keep the layers of fluid moving, $\eta $ is the coefficient of viscosity, A is the cross sectional area of the layer of fluid, V is the velocity and L is the distance between the layers.
So, $\eta = \dfrac{{FL}}{{VA}}$
So, higher the velocity or the velocity gradient lower is the coefficient of viscosity $\eta $
Or lower the velocity gradient higher is the $\eta $.
As we go deeper in the flowing river the velocity decreases and so the viscosity increases, so the fluid friction increases.
So the correct option is (B).
Note: The formula which tells the relation between velocity and viscosity is important. Viscosity is the friction experienced when we pour honey from a jar. Honey is highly viscous. When we pour water or juice from a bottle, we can see it flows freely and quickly. It has very low viscosity.
Complete step by step solution:
As we know that the friction is the type of force which resists the motion of any two solid surfaces or fluid layers. When this friction is experienced inside any fluid then it is called fluid friction or fluid viscosity.
Fluid friction is described as the friction between any two viscous layers of a fluid that are moving with respect to each other. The fluid friction depends upon the viscosity of the fluid and the velocity gradient. The velocity gradient is the rate of change of velocity or simply the ratio of velocity and distance between layers.
As we go deeper inside a flowing river, we require more force to keep the layers flowing with flow.
$ \Rightarrow F = \eta \dfrac{{VA}}{L}$
Where F is the force required to keep the layers of fluid moving, $\eta $ is the coefficient of viscosity, A is the cross sectional area of the layer of fluid, V is the velocity and L is the distance between the layers.
So, $\eta = \dfrac{{FL}}{{VA}}$
So, higher the velocity or the velocity gradient lower is the coefficient of viscosity $\eta $
Or lower the velocity gradient higher is the $\eta $.
As we go deeper in the flowing river the velocity decreases and so the viscosity increases, so the fluid friction increases.
So the correct option is (B).
Note: The formula which tells the relation between velocity and viscosity is important. Viscosity is the friction experienced when we pour honey from a jar. Honey is highly viscous. When we pour water or juice from a bottle, we can see it flows freely and quickly. It has very low viscosity.
Recently Updated Pages
NEET UG Exam Countdown 2026 – Days Left, Tracker & Tips

JEE Main 2026 Admit Card OUT LIVE Soon| Session 2 Direct Download Link

JEE Main 2026 Session 2 City Intimation Slip Expected Soon: Check How to Download

JEE Main 2026 Session 2 Application Form: Reopened Registration, Dates & Fees

JEE Main 2026 Session 2 Registration (Reopened): Last Date, Fees, Link & Process

WBJEE 2026 Registration Started: Important Dates Eligibility Syllabus Exam Pattern

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding the Angle of Deviation in a Prism

Understanding Differential Equations: A Complete Guide

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

CBSE Notes Class 11 Physics Chapter 4 - Laws of Motion - 2025-26

CBSE Notes Class 11 Physics Chapter 14 - Waves - 2025-26

