
The deeper we go inside a flowing river, the fluid friction:
A) decreases
B) increases
C) remains same
D) becomes zero
Answer
219k+ views
Hint: In this question use the concept as you go deeper into a flowing river, you spend more energy as you try to move forward. The speed of swimming decreases. So, the friction increases the deeper we go in a flowing river.
Complete step by step solution:
As we know that the friction is the type of force which resists the motion of any two solid surfaces or fluid layers. When this friction is experienced inside any fluid then it is called fluid friction or fluid viscosity.
Fluid friction is described as the friction between any two viscous layers of a fluid that are moving with respect to each other. The fluid friction depends upon the viscosity of the fluid and the velocity gradient. The velocity gradient is the rate of change of velocity or simply the ratio of velocity and distance between layers.
As we go deeper inside a flowing river, we require more force to keep the layers flowing with flow.
$ \Rightarrow F = \eta \dfrac{{VA}}{L}$
Where F is the force required to keep the layers of fluid moving, $\eta $ is the coefficient of viscosity, A is the cross sectional area of the layer of fluid, V is the velocity and L is the distance between the layers.
So, $\eta = \dfrac{{FL}}{{VA}}$
So, higher the velocity or the velocity gradient lower is the coefficient of viscosity $\eta $
Or lower the velocity gradient higher is the $\eta $.
As we go deeper in the flowing river the velocity decreases and so the viscosity increases, so the fluid friction increases.
So the correct option is (B).
Note: The formula which tells the relation between velocity and viscosity is important. Viscosity is the friction experienced when we pour honey from a jar. Honey is highly viscous. When we pour water or juice from a bottle, we can see it flows freely and quickly. It has very low viscosity.
Complete step by step solution:
As we know that the friction is the type of force which resists the motion of any two solid surfaces or fluid layers. When this friction is experienced inside any fluid then it is called fluid friction or fluid viscosity.
Fluid friction is described as the friction between any two viscous layers of a fluid that are moving with respect to each other. The fluid friction depends upon the viscosity of the fluid and the velocity gradient. The velocity gradient is the rate of change of velocity or simply the ratio of velocity and distance between layers.
As we go deeper inside a flowing river, we require more force to keep the layers flowing with flow.
$ \Rightarrow F = \eta \dfrac{{VA}}{L}$
Where F is the force required to keep the layers of fluid moving, $\eta $ is the coefficient of viscosity, A is the cross sectional area of the layer of fluid, V is the velocity and L is the distance between the layers.
So, $\eta = \dfrac{{FL}}{{VA}}$
So, higher the velocity or the velocity gradient lower is the coefficient of viscosity $\eta $
Or lower the velocity gradient higher is the $\eta $.
As we go deeper in the flowing river the velocity decreases and so the viscosity increases, so the fluid friction increases.
So the correct option is (B).
Note: The formula which tells the relation between velocity and viscosity is important. Viscosity is the friction experienced when we pour honey from a jar. Honey is highly viscous. When we pour water or juice from a bottle, we can see it flows freely and quickly. It has very low viscosity.
Recently Updated Pages
Two discs which are rotating about their respective class 11 physics JEE_Main

A ladder rests against a frictionless vertical wall class 11 physics JEE_Main

Two simple pendulums of lengths 1 m and 16 m respectively class 11 physics JEE_Main

The slopes of isothermal and adiabatic curves are related class 11 physics JEE_Main

A trolly falling freely on an inclined plane as shown class 11 physics JEE_Main

The masses M1 and M2M2 M1 are released from rest Using class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

Understanding Atomic Structure for Beginners

