The centre of mass of two particles lies on the line
(A) Joining the particles
(B) Perpendicular to the line joining the particles
(C) At any angle to this line
(D) None of these
Answer
263.7k+ views
Hint To answer this question we should be knowing the concept of centre of mass. The centre of mass is defined as the distribution of mass in the space in a unique point where the weighted relative position of the distributed mass sums to the value of zero.
Complete step by step answer
We know that the centre of mass of the two particles that is lying on the line joining the particles.
Let us consider that the centre of mass lies at the point C.
So, we can write the expression as follows
$({m_1} + {m_2})x = {m_1}(0) + {m_2}(L)$
So, the expression of x can be written as:
$x = \dfrac{{{m_2}L}}{{{m_1} + {m_2}}}$
So, we can say that the centre of mass of two particles lies on the line joining the particles.
Hence the correct answer is option A
Note We should know that the centre of mass is identified as the position which is relative to the position of the object or system of the objects. It is calculated as the simple average of the position of all the parts of the system, which is weighted according to their masses.
For simple rigid objects with the uniform density, the centre of mass is located at the centroid.
The use of the centre of mass is to find the reference point for calculations in the mechanics that involves the masses which is distributed in the space, such as the linear and angular momentum of the planetary bodies and the rigid body dynamics.
Complete step by step answer
We know that the centre of mass of the two particles that is lying on the line joining the particles.
Let us consider that the centre of mass lies at the point C.
So, we can write the expression as follows
$({m_1} + {m_2})x = {m_1}(0) + {m_2}(L)$
So, the expression of x can be written as:
$x = \dfrac{{{m_2}L}}{{{m_1} + {m_2}}}$
So, we can say that the centre of mass of two particles lies on the line joining the particles.
Hence the correct answer is option A
Note We should know that the centre of mass is identified as the position which is relative to the position of the object or system of the objects. It is calculated as the simple average of the position of all the parts of the system, which is weighted according to their masses.
For simple rigid objects with the uniform density, the centre of mass is located at the centroid.
The use of the centre of mass is to find the reference point for calculations in the mechanics that involves the masses which is distributed in the space, such as the linear and angular momentum of the planetary bodies and the rigid body dynamics.
Recently Updated Pages
JEE Main Mock Test 2025-26: Principles Related To Practical

JEE Main 2025-26 Experimental Skills Mock Test – Free Practice

JEE Main 2025-26 Electronic Devices Mock Test: Free Practice Online

JEE Main 2025-26 Mock Tests: Free Practice Papers & Solutions

JEE Main 2025-26: Magnetic Effects of Current & Magnetism Mock Test

JEE Main Statistics and Probability Mock Test 2025-26

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2025-26

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

