
Recoil velocity is:
A) Equal to velocity of bullet
B) Much greater than velocity of bullet
C) Much smaller than velocity of bullet
D) Cannot say
Answer
149.1k+ views
Hint: Recoil is a gun's backward momentum when it is unloaded. A weapon's recoil velocity is the velocity at which the weapon recoils after being fired. Any action has an equal and opposite response, according to Newton's third law of motion.
Complete answer:
Recoil (often referred to as knock back, kickback or just kick) is the rearward thrust produced when discharging a pistol. In technical terms, the recoil is the product of momentum conservation, since the energy used to propel something will elicit an equal but opposite recreational force, according to Newton's third law, which implies that the forward momentum obtained by the projectile and exhaust gases will be mathematically matched by an equal and opposite momentum exerted back on the gun
Consider two objects A and B collide with each other,
Now, according to Newton’s Third Law,
${F_ {AB}} = - {F_ {BA}} $
${F_ {AB}} $ is forced on A due to B.
${F_ {BA}} $ is forced on B due to A.
Now, Impulse will be,
${F_ {AB}}. {t_ {AB}} = - {F_ {BA}}. {t_ {BA}}$
If we note that the impulse is equal to the momentum, the change in the moments of the objects follows that it is equal, but in the opposite directions. The sum of the transition in moment can be similarly expressed as zero.
\[{m_A} \cdot \Delta {v_A} = - {m_B} \cdot \Delta {v_B}\]
\[\Rightarrow {m_A} \cdot \Delta {v_A} + {m_B} \cdot \Delta {v_B} = 0\]
Hence proving the conservation of momentum.
Recoil velocity is the backward velocity encountered as one fires a projectile through a gunman. The shooter experiences a backward jerk because of the recoil velocity. The recoil velocity is the product of the system's linear momentum conservation. In reality, any projection device has a recoil speed, be it rifle, crossbow, bow and arrow, rocket launchers.
That is because of the law of conservation. The overall pump momentum after shooting is comparable to the overall punch momentum before shooting. Although the mass of the projectile is much greater, the recoil speed is much less than the bullet speed.
Therefore, the correct option is C.
Note: Recoil momentum is transferred to the ground in heavier mounted guns, such as heavy machine guns or artillery pieces, through the mounting platform on which the weapon is installed. The energy gained by the gun is dissipated by a forward-acting counter-recoil force applied to the gun over a period of time after the bullet leaves the muzzle in order to bring the rearward advancing gun to a stop. Modern mounted weapons may use recoil buffering containing springs and hydraulic recoil mechanisms, similar to shock-absorbing suspension on vehicles, to apply this counter-recoiling force.
Complete answer:
Recoil (often referred to as knock back, kickback or just kick) is the rearward thrust produced when discharging a pistol. In technical terms, the recoil is the product of momentum conservation, since the energy used to propel something will elicit an equal but opposite recreational force, according to Newton's third law, which implies that the forward momentum obtained by the projectile and exhaust gases will be mathematically matched by an equal and opposite momentum exerted back on the gun
Consider two objects A and B collide with each other,
Now, according to Newton’s Third Law,
${F_ {AB}} = - {F_ {BA}} $
${F_ {AB}} $ is forced on A due to B.
${F_ {BA}} $ is forced on B due to A.
Now, Impulse will be,
${F_ {AB}}. {t_ {AB}} = - {F_ {BA}}. {t_ {BA}}$
If we note that the impulse is equal to the momentum, the change in the moments of the objects follows that it is equal, but in the opposite directions. The sum of the transition in moment can be similarly expressed as zero.
\[{m_A} \cdot \Delta {v_A} = - {m_B} \cdot \Delta {v_B}\]
\[\Rightarrow {m_A} \cdot \Delta {v_A} + {m_B} \cdot \Delta {v_B} = 0\]
Hence proving the conservation of momentum.
Recoil velocity is the backward velocity encountered as one fires a projectile through a gunman. The shooter experiences a backward jerk because of the recoil velocity. The recoil velocity is the product of the system's linear momentum conservation. In reality, any projection device has a recoil speed, be it rifle, crossbow, bow and arrow, rocket launchers.
That is because of the law of conservation. The overall pump momentum after shooting is comparable to the overall punch momentum before shooting. Although the mass of the projectile is much greater, the recoil speed is much less than the bullet speed.
Therefore, the correct option is C.
Note: Recoil momentum is transferred to the ground in heavier mounted guns, such as heavy machine guns or artillery pieces, through the mounting platform on which the weapon is installed. The energy gained by the gun is dissipated by a forward-acting counter-recoil force applied to the gun over a period of time after the bullet leaves the muzzle in order to bring the rearward advancing gun to a stop. Modern mounted weapons may use recoil buffering containing springs and hydraulic recoil mechanisms, similar to shock-absorbing suspension on vehicles, to apply this counter-recoiling force.
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