
One face of a rectangular glass plate $6\,Cm$ thick is silvered. An object held $8\,Cm$ in front of the fist face, forms an image $12\,Cm$ behind the silvered face. The refractive index of the glass is:
A. 1.2
B. $1.6$
C. $1.5$
D. $1.3$
Answer
220.5k+ views
Hint In the question, the thickness of one of the faces of the rectangular plate is given and the second face of the dimensions is given. By finding the apparent faces of the mirror, then we substitute the known values in the expression of the refractive index, we get the value of the refractive index of the glass.
Formula used:
The expression for finding the refractive index of the glass is
$\mu = \dfrac{{{\text{Real Depth}}}}{{{\text{Apparent Depth}}}}$
Complete step by step answer
Given that,
Thickness of the glass plate, $t = 6\,cm.$
Distance of the object, $u = 8\,cm.$
Distance of the image behind the silvered face, $v = 12\,cm.$
Let x be the apparent position of the silvered surface in terms of centimeter,
Therefore, Distance of object from the mirror $ = $ Distance of image from the mirror.
So, we written the expression as
$x + 8 = 12 + 6 - x$
Performing the arithmetic operations in the above equation, we get
$x = 5\,cm.$
Now, we have to find the refractive index of the glass, we get
Refractive index of the glass is the ratio of the real depth of the mirror to the apparent depth of the mirror.
$\mu = \dfrac{{{\text{Real Depth}}}}{{{\text{Apparent Depth}}}}$
From the question, Real depth $ = 6\,cm.$
Substitute the values in the above equation, we get
$\mu = \dfrac{6}{5}$
Simplify the equation, we get
$\mu = 1.2$
Therefore, the refractive index of the glass is 1.2.
Hence, from the above options, option A is correct.
Note In the question, the value of the actual depth of the mirror is given. we know that apparent depth which means the image is formed due to reflection of the silvered face by the one end of the face through the surface of the mirror. After getting those values, substitute in the equation of the refractive index then we will get the result.
Formula used:
The expression for finding the refractive index of the glass is
$\mu = \dfrac{{{\text{Real Depth}}}}{{{\text{Apparent Depth}}}}$
Complete step by step answer
Given that,
Thickness of the glass plate, $t = 6\,cm.$
Distance of the object, $u = 8\,cm.$
Distance of the image behind the silvered face, $v = 12\,cm.$
Let x be the apparent position of the silvered surface in terms of centimeter,
Therefore, Distance of object from the mirror $ = $ Distance of image from the mirror.
So, we written the expression as
$x + 8 = 12 + 6 - x$
Performing the arithmetic operations in the above equation, we get
$x = 5\,cm.$
Now, we have to find the refractive index of the glass, we get
Refractive index of the glass is the ratio of the real depth of the mirror to the apparent depth of the mirror.
$\mu = \dfrac{{{\text{Real Depth}}}}{{{\text{Apparent Depth}}}}$
From the question, Real depth $ = 6\,cm.$
Substitute the values in the above equation, we get
$\mu = \dfrac{6}{5}$
Simplify the equation, we get
$\mu = 1.2$
Therefore, the refractive index of the glass is 1.2.
Hence, from the above options, option A is correct.
Note In the question, the value of the actual depth of the mirror is given. we know that apparent depth which means the image is formed due to reflection of the silvered face by the one end of the face through the surface of the mirror. After getting those values, substitute in the equation of the refractive index then we will get the result.
Recently Updated Pages
Mass vs Weight: Key Differences Explained for Students

Young’s Double Slit Experiment Derivation Explained

Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2025-26

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding the Electric Field of a Uniformly Charged Ring

