
No work is said to have been done when an object moves at an angle of --------- with the direction of the force.
(A) \[0\]
(B) $90$
(C) $180$
(D) Between $90$ and $180$
Answer
232.8k+ views
Hint We know here that no work is said to have been performed. So, by using the definition of horizontal force and the angle of the object moving, we discover the object moves at an angle and direction force. Then we show that the above query is an example and find an equivalent degree.
Useful formula:
Horizontal force formula,
$F\,n = mg$
Where,
$F$ start subscript, $n$ end subscript, equals \[m,{\text{ }}g\].
Complete step by step answer
Given by,
No work is said to have been done when an object moves at an angle,
We find the angle and direction of force,
For an example,
In this case, the force supplied by the waiter is an upward force and the displacement of the tray is a horizontal displacement if a waiter catches a ray with one hand in a horizontal position. Thus,$90$ degrees would be the angle between them. It would be zero if we quantify the work performed, as the degree of$\cos \,{90^ \circ }$ Cos90 is zero.
Therefore, no work is said to be conducted when the force vector and displacement vector are perpendicular to each other.
Hence,
Thus, option B is the correct answer.
Note According to that the work performed on an object in a given motion direction is equal to the force times the displacement times the angle cosine. We omit the cosine term when considering force parallel to the direction of motion, since it is equal to one, which does not alter the expression.
Useful formula:
Horizontal force formula,
$F\,n = mg$
Where,
$F$ start subscript, $n$ end subscript, equals \[m,{\text{ }}g\].
Complete step by step answer
Given by,
No work is said to have been done when an object moves at an angle,
We find the angle and direction of force,
For an example,
In this case, the force supplied by the waiter is an upward force and the displacement of the tray is a horizontal displacement if a waiter catches a ray with one hand in a horizontal position. Thus,$90$ degrees would be the angle between them. It would be zero if we quantify the work performed, as the degree of$\cos \,{90^ \circ }$ Cos90 is zero.
Therefore, no work is said to be conducted when the force vector and displacement vector are perpendicular to each other.
Hence,
Thus, option B is the correct answer.
Note According to that the work performed on an object in a given motion direction is equal to the force times the displacement times the angle cosine. We omit the cosine term when considering force parallel to the direction of motion, since it is equal to one, which does not alter the expression.
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