
Match List-I with list-II: Name of Oxo acid, the Oxidation state of ‘P’.
List-IName of Oxo acid List-IIThe oxidation state of ‘P’ (a) Hypophosphorus acid (i) \[ + 5\] (b) Orthophosphoric acid (ii) \[ + 4\] (c) Hypophosphoric acid (iii) \[ + 3\] (d) Orthophosphorus acid (iv) \[ + 2\] - - (v) \[ + 1\]
Choose the correct answer from the options given below:
1. \[(a) - (iv),(b) - (v),(c) - (ii),(d) - (iii)\]
2. \[(a) - (v),(b) - (iv),(c) - (ii),(d) - (iii)\]
3. \[(a) - (v),(b) - (i),(c) - (ii),(d) - (iii)\]
4. \[(a) - (iv),(b) - (i),(c) - (ii),(d) - (iii)\]
List-IName of Oxo acid | List-IIThe oxidation state of ‘P’ | |
(a) | Hypophosphorus acid | (i) \[ + 5\] |
(b) | Orthophosphoric acid | (ii) \[ + 4\] |
(c) | Hypophosphoric acid | (iii) \[ + 3\] |
(d) | Orthophosphorus acid | (iv) \[ + 2\] |
- | - | (v) \[ + 1\] |
Answer
164.1k+ views
Hint: Oxidation states simplify the work of determining what is oxidised and what is reduced in redox reactions. A positive number results in an electron being lost, while a negative number results in an electron being gained.
Complete Step by Step Solution:
1. Oxidation state: An oxidation number indicates the oxidation state of an element within a compound according to a set of rules based on the assumption that electrons within a covalent bond belong entirely to the more electronegative element.
2. Oxidizing agent: A reagent that increases the oxidation number of an element in the compound is known as an oxidizing agent.
3. Reducing agent: A reagent that decreases the oxidation number of an element of the compound is known as a reducing agent.
4. The algebraic sum of the oxidation number of all atoms in a compound is equal to zero but for the polyatomic ions, the algebraic sum of all the oxidation numbers of all atoms of the ion is equal to the charge on the ion.
5. The oxidation number of Hydrogen and Oxygen is \[ + 1\,and\, - 2\].
6. The formula of Hypophosphorous acid is \[{H_3}P{O_2}\]and the calculation for oxidation number is expressed below:
Let us assume, the oxidation number of Phosphorus is x:
\[3 \times 1 + x + 2 \times \left( { - 2} \right) = 0\]
\[3 + x - 4 = 0\]
\[x - 1 = 0\]
\[x = + 1\]
7. The general formula of Orthophosphoric acid, Hypophosphoric acid, and Orthophosphorus acid is \[{H_3}P{O_4},{H_4}{P_2}{O_6},{H_3}P{O_3}\].
8. Similarly calculate the oxidation number of the other three Phosphorus compounds.
9. The oxidation number of Orthophosphoric acid, Hypophosphoric acid, and Orthophosphoric acid is \[ + 5, + 4, + 3\].
The correct option is c.
Additional information:
1. The oxidation number of Oxygen in Peroxides \[({H_2}{O_2},N{a_2}{O_2})\]is \[ - 1\]and in Super oxides \[\left( {K{O_2},Rb{O_2}} \right)\]is \[ - {\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 2}}\right.\kern-\nulldelimiterspace}
\!\lower0.7ex\hbox{$2$}}\].
2. The oxidation number of Hydrogen is \[ - 1\] when it is attached to the metals in binary compounds \[(NaH,LiH)\].
3. The oxidation number of an atom in a free or uncombined state \[\left( {{H_2},{O_2},C{l_2}} \right)\]is zero.
4. Ions are composed of only one atom\[\left( {N{a^ + }} \right)\], the oxidation number equals the charge on the ion\[( + 1)\].
Note: An element that has a positive oxidation number is metallic, whereas an element that has a negative or positive oxidation number is non-metallic.
Complete Step by Step Solution:
1. Oxidation state: An oxidation number indicates the oxidation state of an element within a compound according to a set of rules based on the assumption that electrons within a covalent bond belong entirely to the more electronegative element.
2. Oxidizing agent: A reagent that increases the oxidation number of an element in the compound is known as an oxidizing agent.
3. Reducing agent: A reagent that decreases the oxidation number of an element of the compound is known as a reducing agent.
4. The algebraic sum of the oxidation number of all atoms in a compound is equal to zero but for the polyatomic ions, the algebraic sum of all the oxidation numbers of all atoms of the ion is equal to the charge on the ion.
5. The oxidation number of Hydrogen and Oxygen is \[ + 1\,and\, - 2\].
6. The formula of Hypophosphorous acid is \[{H_3}P{O_2}\]and the calculation for oxidation number is expressed below:
Let us assume, the oxidation number of Phosphorus is x:
\[3 \times 1 + x + 2 \times \left( { - 2} \right) = 0\]
\[3 + x - 4 = 0\]
\[x - 1 = 0\]
\[x = + 1\]
7. The general formula of Orthophosphoric acid, Hypophosphoric acid, and Orthophosphorus acid is \[{H_3}P{O_4},{H_4}{P_2}{O_6},{H_3}P{O_3}\].
8. Similarly calculate the oxidation number of the other three Phosphorus compounds.
9. The oxidation number of Orthophosphoric acid, Hypophosphoric acid, and Orthophosphoric acid is \[ + 5, + 4, + 3\].
The correct option is c.
Additional information:
1. The oxidation number of Oxygen in Peroxides \[({H_2}{O_2},N{a_2}{O_2})\]is \[ - 1\]and in Super oxides \[\left( {K{O_2},Rb{O_2}} \right)\]is \[ - {\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 2}}\right.\kern-\nulldelimiterspace}
\!\lower0.7ex\hbox{$2$}}\].
2. The oxidation number of Hydrogen is \[ - 1\] when it is attached to the metals in binary compounds \[(NaH,LiH)\].
3. The oxidation number of an atom in a free or uncombined state \[\left( {{H_2},{O_2},C{l_2}} \right)\]is zero.
4. Ions are composed of only one atom\[\left( {N{a^ + }} \right)\], the oxidation number equals the charge on the ion\[( + 1)\].
Note: An element that has a positive oxidation number is metallic, whereas an element that has a negative or positive oxidation number is non-metallic.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

Solutions Class 12 Notes: CBSE Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

Electrochemistry Class 12 Notes: CBSE Chemistry Chapter 2
