
What is the mass of a person if he does 3600 J of work in climbing a tree 6m tall? \[(g = 10m/{s^2})\]
(A) 70 kg
(B) 60 kg
(C) 85 kg
(D) 52 kg
Answer
218.7k+ views
Hint Potential energy is defined as the work done to change the configuration of the body. If a body is raised to a height, some work must be done to change its configuration from the ground state to that elevated state. This work done is stored in the form of potential energy in the body.
Complete step-by-step solution
We are given that a man does 3600J of work in climbing a tree. As there is no other force involved except the force due to gravity, this work done will be stored as potential energy inside the man due to virtue of his height. Potential energy of a body of mass m and height h on planet earth \[(g = 10m/{s^2})\] is given by
\[E = mgh\]
This potential energy is given in the question as 3600J, substituting this in the equation:
\[3600 = m \times 10 \times 6\]
\[m = 60kg\]
Therefore, the mass of the man is 60kg. So, the correct answer is given by option B
Note: Energy is neither created nor destroyed. So, if the man jumps from this height, then all of this potential energy will be converted into kinetic energy. Moments before touching the ground, he will have the highest kinetic energy and his velocity just before touching the ground will be \[v = \sqrt {2gr} \].
Complete step-by-step solution
We are given that a man does 3600J of work in climbing a tree. As there is no other force involved except the force due to gravity, this work done will be stored as potential energy inside the man due to virtue of his height. Potential energy of a body of mass m and height h on planet earth \[(g = 10m/{s^2})\] is given by
\[E = mgh\]
This potential energy is given in the question as 3600J, substituting this in the equation:
\[3600 = m \times 10 \times 6\]
\[m = 60kg\]
Therefore, the mass of the man is 60kg. So, the correct answer is given by option B
Note: Energy is neither created nor destroyed. So, if the man jumps from this height, then all of this potential energy will be converted into kinetic energy. Moments before touching the ground, he will have the highest kinetic energy and his velocity just before touching the ground will be \[v = \sqrt {2gr} \].
Recently Updated Pages
Two discs which are rotating about their respective class 11 physics JEE_Main

A ladder rests against a frictionless vertical wall class 11 physics JEE_Main

Two simple pendulums of lengths 1 m and 16 m respectively class 11 physics JEE_Main

The slopes of isothermal and adiabatic curves are related class 11 physics JEE_Main

A trolly falling freely on an inclined plane as shown class 11 physics JEE_Main

The masses M1 and M2M2 M1 are released from rest Using class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

