
Mark the element which can displace the other three halogens from their compounds.
(A) Fluorine
(B) Chlorine
(C) Bromine
(D) Iodine
Answer
163.2k+ views
Hint: All the given elements are halogens. Halogens are very reactive as they contain seven electrons in the valence shell and thus require only one electron to complete their octet. For an element to displace another element, it should have higher reactivity.
Complete Step by Step Solution:
As the order of reactivity of halogens is:
Fluorine > Chlorine > Bromine > Iodine
This means fluorine is the most reactive of all the halogens. The reason for the higher reactivity of fluorine is its small size and higher electronegativity. Hence, fluorine is the element that can displace the other three halogens from their compounds.
Fluorine can displace chlorine from sodium chloride ($NaCl$) to form sodium fluoride ($NaF$).

Similarly, it can displace bromine from sodium bromide ($NaBr$) to form sodium fluoride ($NaF$).

Also, it can displace iodine from sodium iodide ($NaI$) to form sodium fluoride ($NaF$).

Correct Option: (A) Fluorine
Additional Information: Due to the smallest size of fluorine among halogens, its melting and boiling points are very low. Also, the ionisation energy, that is the energy required to remove an electron from the valence shell of fluorine, is very high.
Note: Fluorine (${{F}_{2}}$) and chlorine ($C{{l}_{2}}$) are gases; bromine ($B{{r}_{2}}$) is a liquid; and iodine (${{I}_{2}}$) is a solid. The halogens can form metal halides, hydrogen halides, organohalogens, interhalogen compounds, and polyhalogenated compounds.
Complete Step by Step Solution:
As the order of reactivity of halogens is:
Fluorine > Chlorine > Bromine > Iodine
This means fluorine is the most reactive of all the halogens. The reason for the higher reactivity of fluorine is its small size and higher electronegativity. Hence, fluorine is the element that can displace the other three halogens from their compounds.
Fluorine can displace chlorine from sodium chloride ($NaCl$) to form sodium fluoride ($NaF$).

Similarly, it can displace bromine from sodium bromide ($NaBr$) to form sodium fluoride ($NaF$).

Also, it can displace iodine from sodium iodide ($NaI$) to form sodium fluoride ($NaF$).

Correct Option: (A) Fluorine
Additional Information: Due to the smallest size of fluorine among halogens, its melting and boiling points are very low. Also, the ionisation energy, that is the energy required to remove an electron from the valence shell of fluorine, is very high.
Note: Fluorine (${{F}_{2}}$) and chlorine ($C{{l}_{2}}$) are gases; bromine ($B{{r}_{2}}$) is a liquid; and iodine (${{I}_{2}}$) is a solid. The halogens can form metal halides, hydrogen halides, organohalogens, interhalogen compounds, and polyhalogenated compounds.
Recently Updated Pages
JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

JEE Main 2025 Session 2: Exam Date, Admit Card, Syllabus, & More

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Types of Solutions

Degree of Dissociation and Its Formula With Solved Example for JEE

Classification of Drugs

Instantaneous Velocity - Formula based Examples for JEE

Other Pages
Haloalkanes and Haloarenes

CBSE Class 12 Chemistry Chapter 3 Chemical Kinetics – NCERT Solutions 2025–26

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 12 Chemistry In Hindi Chapter 2 Solutions Hindi Medium

NCERT Solutions for Class 12 Chemistry Chapter 4 The D and F Block Elements

Chemical Kinetics Class 12 Notes: CBSE Chemistry Chapter 3
